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svetoff [14.1K]
3 years ago
8

Please help me find the area of the trapezoid

Mathematics
2 answers:
VLD [36.1K]3 years ago
8 0
Well, the formula is: A= [(b1+b2)/2]h
So first we have to add 8.52 and 22.2, which is 30.72. Now, divide this by two, which would give us 15.36. Then, you multiply the height, which is 9.86. This will give us the answer of 151.4496 cm squared.
Hope this helps!
alex41 [277]3 years ago
5 0
Formulas:
A= (b1+b2) /2 X h

A= (22.2+8.52) x 9.86
A=30.72x9.86
A= 302.90
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How to find the average squared distance between the points of the unit disk and the point (1,1)
ddd [48]
The unit disk can be parameterized by the function

\mathbf p(r,\theta)=(r\cos\theta,r\sin\theta)

where 0\le r\le 1 and 0\le\theta\le2\pi. The squared distance between any point in this region (x,y)=(r\cos\theta,r\sin\theta) and the point (1, 1) is

(x-1)^2+(y-1)^2=(r\cos\theta-1)^2+(r\sin\theta-1)^2
=(r^2\cos^2\theta-2r\cos\theta+1)+(r^2\sin^2\theta-2r\sin\theta+1)
=r^2(\cos^2\theta+\sin^2\theta)-2r(\cos\theta-\sin\theta)+2
=r^2-2r(\cos\theta-\sin\theta)+2

The average squared distance is then going to be the ratio of [the sum of all squared distances between every point in the disk and the point (1, 1)] to [the area of the disk], i.e.

\dfrac{\displaystyle\iint_{x^2+y^2
=\dfrac{\displaystyle\int_{\theta=0}^{\theta=2\pi}\int_{r=0}^{r=1}[r^2-2r(\cos\theta-\sin\theta)+2]r\,\mathrm dr\,\mathrm d\theta}{\displaystyle\int_{\theta=0}^{\theta=2\pi}\int_{r=0}^{r=1}r\,\mathrm dr\,\mathrm d\theta}
=\dfrac{\frac{5\pi}2}\pi=\dfrac52
5 0
3 years ago
Consider the sequence 3, 6, 12, 24, 48, .... (a) Write a recursive rule to represent the sequence. (b) Write an explicit rule to
saveliy_v [14]

Answer:

  a. a[1] = 3; a[n] = 2a[n-1]

  b. a[n] = 3·2^(n-1)

  c. a[15] = 49,152

Step-by-step explanation:

Each term of the given sequence is 2 times the previous term. (This description is the basis of the recursive formula.) That is, the terms of the given sequence have a common ratio of 2. This means the sequence is geometric, so the formulas for explicit and recursive rules for a geometric sequence apply.

The first term is 3, and the common ratio is 2.

<h3>(a)</h3>

The recursive rule is ...

  a[1] = 3

  a[n] = 2×a[n-1]

__

<h3>(b)</h3>

The explicit rule is ...

  a[n] = a[1]×r^(n-1)

  a[n] = 3×2^(n-1)

__

<h3>(c)</h3>

The 15th term is ...

  a[15] = 3×2^(15-1) = 3×2^14

  a[15] = 49,152

5 0
3 years ago
Which us the simplified form of <br><img src="https://tex.z-dn.net/?f=%20%7Bp%7D%5E%7B0%7D%20" id="TexFormula1" title=" {p}^{0}
Mice21 [21]
1
anything with the power of 0=1
3 0
3 years ago
Help this is due tomorrow!!!
r-ruslan [8.4K]

Answer:

V=4/3*3.14*r^3

V=4/3*3.14*3^3

V=113.1

Volume of Himiphere= Volume of sphere/2

113.1/2

V=56.6

Step-by-step explanation:

The answer is 56.6

4 0
2 years ago
Read 2 more answers
What is the value of x?
Cloud [144]
I think the answer is D. 170 but if I’m wrong I’m totally srry
4 0
3 years ago
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