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svetoff [14.1K]
3 years ago
8

Please help me find the area of the trapezoid

Mathematics
2 answers:
VLD [36.1K]3 years ago
8 0
Well, the formula is: A= [(b1+b2)/2]h
So first we have to add 8.52 and 22.2, which is 30.72. Now, divide this by two, which would give us 15.36. Then, you multiply the height, which is 9.86. This will give us the answer of 151.4496 cm squared.
Hope this helps!
alex41 [277]3 years ago
5 0
Formulas:
A= (b1+b2) /2 X h

A= (22.2+8.52) x 9.86
A=30.72x9.86
A= 302.90
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What is the measure of cº?<br> A. 7.5°<br> B. 15<br> C. 30°<br> D. 45
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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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3 years ago
Log based question, i just need help with parts b and c
Tanya [424]

Answer:

b) There is translation 3 units to the right and 1 unit up

c) The domain is {x I x > 3}

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Step-by-step explanation:

* Lets revise the rule of the translation

- If the function f(x) translated horizontally to the right  

 by h units, then the new function g(x) = f(x - h)

- If the function f(x) translated horizontally to the left  

 by h units, then the new function g(x) = f(x + h)

- If the function f(x) translated vertically up  

 by k units, then the new function g(x) = f(x) + k

- If the function f(x) translated vertically down  

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* Now lets solve the problem

b) ∵ f(x) = log_{2} (x-3)+1

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  to the right

∵ We add the parent function by 1, that means there is a translation

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* There is translation 3 units to the right and 1 unit up

c) To find the domain of the function, find the values of x which

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∵ log_{2}(0) is undefined

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∵ x - 3 = 0 ⇒ add 3 to both sides

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* The domain is {x I x > 3}

∵ x can not be 3

∴ There is a vertical asymptote, its equation is x = 3

* The equation of the asymptote is x = 3

# Look to the attached graph for more understand for the domain

  and the equation of the asymptote

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3 years ago
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