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WITCHER [35]
3 years ago
8

This pattern repeats every 4 terms, and the rule is triangle, plus, star, circle. What is the shape in the 16th term of this pat

tern?
Mathematics
1 answer:
Alexxandr [17]3 years ago
5 0

Answer:

Fill in the blanks to make the following statements true. Also named the property used.  

a. (-5) + (-4) = ___ + (-5),

b. 4 + __ = 4,

c. - 53 + ___ = - 53,  

d. 4 + [(-5) + (7)] = [4 + (7)] + ___,

e. 25 + [(-50) + 5 ] = (25 + 5) + ___,

f. (-4) + ___ = -4,

g. 4 + (-4) = ___,

h. 5 + ___ = 0 ,

Step-by-step explanation:

Fill in the blanks to make the following statements true. Also named the property used.  

a. (-5) + (-4) = ___ + (-5),

b. 4 + __ = 4,

c. - 53 + ___ = - 53,  

d. 4 + [(-5) + (7)] = [4 + (7)] + ___,

e. 25 + [(-50) + 5 ] = (25 + 5) + ___,

f. (-4) + ___ = -4,

g. 4 + (-4) = ___,

h. 5 + ___ = 0 ,

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Answer:

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Given: g(x)= sqrt x-4 and h(X)=2x-8 . What are the restrictions on the domain of g*h?
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Given : g(x) = \sqrt{x-4}  and h(x)=2x-8.

Let us find g*h(x) function now.

g*h(x) = g(x) * h(x) = \sqrt{x-4}*(2x-8)

Or g*h(x) =(2x-8)\sqrt{x-4}.

He have square root(x-4) in composite function f*h(x).

So, we need to find the domain, we need to check for that values of x's, square root(x-4) would be defined.

Square roots are undefined for negative values.

Therefore, we can setup an inequality for it's domain x-4≥0.

Adding 4 on both sides, we get

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Therefore, Domain is all values greater than or equal to 4.

But, restrictions would be all values less than 4 (because less than 4 would give a negative number inside square root).


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