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krok68 [10]
2 years ago
13

Find the perpendicular distance from the pointp(6, 4, 2)to the xy-plane.

Mathematics
1 answer:
Stells [14]2 years ago
7 0

, 4, 2)to the xy............................................

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What value of b will cause the system to have an infinite
m_a_m_a [10]

Answer:

b=6

Step-by-step explanation:

<u><em>The correct question is</em></u>

What value of b will cause the system to have an infinite number of solutions?

y = 6x – b

–3x + 1/2y = –3

we have

y=6x-b ----->equation A

-3x+\frac{1}{2}y=-3 -----> equation B

we know that

If the system has infinite number of solutions then, the equation A must be equal to the equation B

so

isolate variable y in the equation B

-3x+\frac{1}{2}y=-3

Multiply by 2 both sides

-6x+y=-6

y=6x-6 -------> new equation B

To find out the value of b, equate equation A and equation B

6x-b=6x-6

b=6

4 0
2 years ago
A ladder leans against the wall and reaches a
stich3 [128]
The base would represent the side adjacent to the angle and the height up the wall would be the opposite side. Using the tangent^-1 (opposite over adjacent) function we are looking for the tan^-1 of 6/24 or 14.04°
5 0
2 years ago
Sarah has some chocolates.
kakasveta [241]

Answer:

24:8 which is also just 6:2 or 3:1

Step-by-step explanation:

There are many ways you can write this, and this is what I think hope this helps

8 0
3 years ago
Please help me, this is frustrating!
kolbaska11 [484]
Check the picture below


for the DB length, make sure your calculator is in Degree mode, since the angles are in degrees.

5 0
2 years ago
Read 2 more answers
QS¯¯¯¯¯¯¯ bisects ∠PQR . If m∠PQS = 5x and m∠RQS = 2x + 6, then what is m∠PQR ? m∠PQR is
soldi70 [24.7K]

Answer:

PQR = 20

Step-by-step explanation:

Given

Bisector: QS

PQS = 5x

RQS = 2x + 6

Required

Determine PQR

Since PQR is bisected to PQS and RQS, we have that

PQS = RQS

Substitute expressions for PQS and RQS

5x = 2x + 6

Collect Like Terms

5x - 2x = 6

3x = 6

Divide both sides by 3

x = 2

Solving for PQR;

PQR = PQS + RQS

PQR = 5x + 2x + 6

PQR = 7x + 6

Substitute 2 for x

PQR = 7 * 2 + 6

PQR = 14 + 6

PQR = 20

4 0
3 years ago
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