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2 years ago

The sum of the areas of two circles is 80n square meters. Find the length of a radius of each circle if

Mathematics

1 answer:

astra-53 [7]2 years ago

4 0

Answer:

8 meters.

Step-by-step explanation:

Let the 2 radii be x and 2x, then
π x^2 + π (2x)^2 = 80π

π x^2 + π 4x^2= 80π

x^2 + 4x^2= 80

5x^2 = 80

x^2 = 16

x = 4.

So the radius of the larger circle = 2*4 = 8 m.

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3 years ago

If sec ⁡ θ = − 2 secθ=−2 and the reference angle of θ θ is 6 0 ∘ 60 ∘ , find both angles in degrees from 0 ∘ ≤ θ < 36 0 ∘ 0 ∘

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2 years ago

Jai Narayan sells two radio sets for 2288 each.

san4es73 [151]

Answer:

Step-by-step explanation:

S.P of each radio=$ 2288

Total S.P= $2\times 2288=$ $4576

Gain=10%

Lose=10%

C.P= $\frac{S.P\times 100}{100+gain(in\;percent)}$

C.P= $\frac{S.P\times 100}{100-loss(in\;percent)}$

By using the formula

C.P of one radio= $\frac{2288\times 100}{110}=$ $2080

C.P of another radio= $\frac{2288\times 100}{100-10}$ =$2542.2

Total C.P of two radios=2080+2542.2=$4622.2

Total C.P >Total S.P

Loss=S.P-C.P

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5 0

3 years ago

Assume that 200 babies are born to 200 couples treated with the XSORT method of gender selection that is claimed to make girls m

JulsSmile [24]

Answer:

a) test statistic = 2.12

b) p-value = 0.017

c) we reject the Null hypothesis

Step-by-step explanation:

Given data :

N = 200

girls (x) = 115 , Boys = 85

p = x / n = 115 / 200 = 0.575

significance level ( ∝ ) = 0.1

aim : test whether the proportion of girls births after the treatment is greater than 50% that occurs without any treatment .

A) Determine the test statistic

H0 : p = 0.5

Ha : p > 0.5

to determine the test statistic we will apply the z distribution at ( ∝ ) = 0.1

Z - test statistic = ( 0.575 - 0.5) / $\sqrt{0.5*0.5 / 200}$ = 2.12

b) determine the p-value

The P-value can be determined using the normal standard table

P-value = 1 - p(Z< 2.12 ) = 1 - 0.9830 = 0.017

c) Given that the p value ( 0.017 ) < significance level ( 0.1 )

we will reject the H0 because there is evidence showing that proportion of girls birth is > 50%

3 0

2 years ago

The measure of angle A is 15°, and the length of side

dangina [55]

Answer:

Part 1) $AB=30.9\ units$

Part 2) $AC=29.9\ units$

Step-by-step explanation:

The picture of the question in the attached figure

Part 1

Find the length side AB

we know that

$sin(A)=\frac{BC}{AB}$ ----> by SOH (opposite side divided by the hypotenuse)

substitute the given values

$sin(15^o)=\frac{8}{AB}$

solve for AB

$AB=\frac{8}{sin(15^o)}=30.9\ units$

Part 2

Find the length side AC

we know that

$tan(A)=\frac{BC}{AC}$ ----> by TOA (opposite side divided by the adjacent side)

substitute the given values

$tan(15^o)=\frac{8}{AC}$

solve for AC

$AC=\frac{8}{tan(15^o)}=29.9\ units$

8 0

3 years ago