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2 years ago

The sum of the areas of two circles is 80n square meters. Find the length of a radius of each circle if

Mathematics

1 answer:

astra-53 [7]2 years ago

4 0

Answer:

8 meters.

Step-by-step explanation:

Let the 2 radii be x and 2x, then
π x^2 + π (2x)^2 = 80π

π x^2 + π 4x^2= 80π

x^2 + 4x^2= 80

5x^2 = 80

x^2 = 16

x = 4.

So the radius of the larger circle = 2*4 = 8 m.

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In the figure,Line x is parallel to line y. identify the angles congruent to angle 3

san4es73 [151]

Answer:

For example, slide ∠ 1 down the transversal and it will coincide with ∠2. are equal in measure. If two parallel lines are cut by a transversal, the corresponding angles are congruent. If two lines are cut by a transversal and the corresponding angles are congruent, the lines are parallel.

Step-by-step explanation:

8 0

2 years ago

K = 8k + 28 I'm confused, please help me!

AveGali [126]

K=8k+28

subtract 8k from both side

-7k = 28

divide both side by -7

k= -4

3 0

3 years ago

What is the vertex of the graph of y = x2 + 4x? (–2, –12) (–2, –8) (–2, –6) (–2, –4)

SCORPION-xisa [38]

Answer: The vertex of the parabola (quadratic function) is (-2,-4)

Fourth option: (-2,-4)

Solution:

y=x^2+4x

y=ax^2+bx+c; a=1, b=4, c=0

Vertex: V=(h,k)

h=-b/(2a)

h=-4/(2(1))

h=-4/2

h=-2

y=x^2+4x

k=y=h^2+4h

k=(-2)^2+4(-2)

k=4-8

k=-4

Vertex: V=(h,k)

Vertex: V=( -2, -4)

3 0

3 years ago

Read 2 more answers

A cone and a triangular pyramid have a height of 9.3 m

Otrada [13]

Answer:

$x=17.1\ in$

Step-by-step explanation:

The complete question is

A cone and a triangular pyramid have a height of 9.3 m and their cross-sectional areas are equal at every level parallel to their respective bases. The radius of the base of the cone is 3 in and the other leg (not x) of the triangle base of the triangular pyramid is 3.3 in

What is the height, x, of the triangle base of the pyramid? Round to the nearest tenth

The picture of the question in the attached figure

we know that

If their cross-sectional areas are equal at every level parallel to their respective bases and the height is the same, then their volumes are equal

Equate the volume of the cone and the volume of the triangular pyramid

$\frac{1}{3}\pi r^{2}H=\frac{1}{3}[\frac{1}{2}(b)(h)H]$

simplify

$\pi r^{2}=\frac{1}{2}(b)(h)$

we have

$r=3\ in\\b=3.3\ in\\h=x\ in\\pi=3.14$

substitute the given values

$(3.14)(3)^{2}=\frac{1}{2}(3.3)(x)$

solve for x

$28.26=\frac{1}{2}(3.3)(x)$

$x=28.26(2)/3.3\\x=17.1\ in$

7 0

3 years ago

Read 2 more answers

George walked around the entire perimeter of his rectangular garden. The length of his garden was 12 yards and the width was 8 y

Marina86 [1]

To find perimeter, you use this equation for a parallelogram:
2l+2w=p
Let’s not put the numbers in,
2(12)+2(8)
24+16
40
So b, 40 yards is how much he walked.

To

8 0

3 years ago