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2 years ago

The sum of the areas of two circles is 80n square meters. Find the length of a radius of each circle if

Mathematics

1 answer:

astra-53 [7]2 years ago

4 0

Answer:

8 meters.

Step-by-step explanation:

Let the 2 radii be x and 2x, then
π x^2 + π (2x)^2 = 80π

π x^2 + π 4x^2= 80π

x^2 + 4x^2= 80

5x^2 = 80

x^2 = 16

x = 4.

So the radius of the larger circle = 2*4 = 8 m.

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Quadrilateral A has side lengths 6, 9, 9, and 12. Quadrilateral B is a scaled copy of Quadrilateral A, with its shortest side of

Alekssandra [29.7K]

Answer:

Look below

Step-by-step explanation:

Ok, you got a Quadrilateral with the side lengths 6, 9, 9, 12

The shortest of B is 2

Find the scale factor of the A to B

6 -> 2

6/2 = 3

Scale factor is 3

Now divide all the sides by scale factor

6/3, 9/3, 9/3, 12/3 = 2, 3, 3, 4

Add them all together to get the perimeter

2+3+3+4 = 12

Perimeter of B is 12

5 0

3 years ago

PLSSSSS HELPPP solve for x, round to nearest tenth

inessss [21]

Answer:

17.6

Step-by-step explanation:

7 0

2 years ago

What is the y-intercept Of the function Represented by the table of values belowX -2 1 2 4 7 y 15 6 3 -3 -12

Kipish [7]

Given:

The table of values.

To find:

The y-intercept of the given function.

Solution:

The table of values represents a linear function because the rate of change is constant.

Consider any two points from the given table. Let the two points are (-2,15) and (1,6). Then the equation of the linear function is

$y-y_1=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)$

$y-15=\dfrac{6-15}{1-(-2)}(x-(-2))$

$y-15=\dfrac{-9}{1+2}(x+2)$

$y-15=\dfrac{-9}{3}(x+2)$

$y-15=-3(x+2)$

Adding 15 on both sides, we get

$y=-3x-6+15$

$y=-3x+9$

Putting x=0, we get

$y=-3(0)+9$

$y=0+9$

$y=9$

The y-intercept is 9. Therefore, the correct option is C.

8 0

2 years ago

Read 2 more answers

I have a two digit number the sum of the digits is 12 the first digit is 4 Less Than 3 times the second what is my number

nignag [31]

Answer:

Step-by-step explanation:

Let the first digit = x

Let the second digit =y

x + y = 12

x + 4 = 3*y

===========

From the second equation, we learn that x = 3y - 4

Put that into the first equation.

3y - 4 + y = 12 Combine the left side

4y - 4 = 12 Add 4 to both sides

4y = 16 Divide by 4

4y/4 = 16/4

y = 4

=================

x + 4 = 12

x + 4 - 4 = 12-4

x = 8

So the number is 84

3 0

2 years ago

Choose one of the factors of 500x3 + 108y18

sammy [17]

Answer:

Option C

Therefore, one of the factors of $500x^3 +108y^\left (18\right )$ is $(5x+3y^6)$ .

Step-by-step explanation:

Given: $500x^3 +108y^\left (18\right )$

the common factor from $500x^3$ and $108y^\left (18\right )$ is 4.

therefore, $4\cdot \left ( 125x^3+27y^\left (18\right ) \right )$

$4\cdot \left ( (5x)^3+(3y^6)^3 \right))$

Now, use the formula for above expression: $(a^3+b^3)=(a+b)(a^2-ab+b^2)$

here, $a=5x$ and $b=3y^6$

$( (5x)^3+(3y^6)^3 \right))$ $=(5x+3y^6)(25x^2-15xy^6+9y^12)$

Therefore, we have

$500x^3 +108y^\left (18\right )$ $=4\cdot (5x+3y^6)\left (25x^2-15xy^6+9y^\left ( 12 \right ) \right )$

Therefore, one of the factors of $500x^3 +108y^\left (18\right )$ is $(5x+3y^6)$ .

7 0

3 years ago

Read 2 more answers