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3 years ago

What is the volume of 1.60 grams of O2 gas at STP?

Mathematics

2 answers:

Mariulka [41]3 years ago

5 0

The answer is 1.12 or d

Verizon [17]3 years ago

3 0

Answer: The volume of given amount $O_2$ at STP is 1.12 L

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Given mass of oxygen = 1.6 g

Molar mass of oxygen = 32 g/mol

Putting values in above equation, we get:

$\text{Moles of oxygen}=\frac{1.6g}{32g/mol}=0.05mol$

At STP:

1 mole of a gas occupies 22.4 liters of volume.

So, 0.05 moles of oxygen gas will occupy = $\frac{22.4L}{1mol}\times 0.05mol=1.12L$ of volume.

Thus, the volume of given amount $O_2$ at STP is 1.12 L

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2 years ago

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2 years ago

A mistake was made in mixing the lemonade— PLEASE HELP!!

beks73 [17]

Answer:

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$x + y = 10$

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Step-by-step explanation:

Part A:

The inicial concentration of the lemonade is 50%, and the volume is 4 quarts, and we will add x quarts of a lemonade with a concentration of 100%, so the total volume will be y, and the concentration will be 0.7, so we have that:

$4 + x = y$

$0.5*4 + 1*x = 0.7*y$

Using the value of y from the first equation in the second one, we have:

$2 + x = 0.7*(4 + x)$