Question

What is the volume of 1.60 grams of O2 gas at STP?

Answer 1

The answer is 1.12 or d

Answer 2

Answer: The volume of given amount $O_2$ at STP is 1.12 L

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Given mass of oxygen = 1.6 g

Molar mass of oxygen = 32 g/mol

Putting values in above equation, we get:

$\text{Moles of oxygen}=\frac{1.6g}{32g/mol}=0.05mol$

At STP:

1 mole of a gas occupies 22.4 liters of volume.

So, 0.05 moles of oxygen gas will occupy = $\frac{22.4L}{1mol}\times 0.05mol=1.12L$ of volume.

Thus, the volume of given amount $O_2$ at STP is 1.12 L