Given :
The diagonals of rhombus ABCD intersect at E.
∠CAD = 20°.
To Find :
The angle ∠CDA.
Solution :
We know, diagonals of a rhombus bisects each other perpendicularly.
So, ∠DEA = 90°.
In triangle ΔEAD :
∠EAD + ∠AED + ∠EDA = 180°
20° + 90° + ∠EDA = 180°
∠EDA = 70°
Now, we know diagonal of rhombus also bisect the angle between two sides .
So, ∠CDA = 2∠EDA
∠CDA = 2×70°
∠CDA =140°
Therefore, ∠CDA is 140°.
It is just the multiplication of vectors. We'll multiply corresponding pairs together. The general formula for the pairs of (
;
) and (
;
) is
*
+
*
= (-6)*(-3)+4*6=18+24=42
A=base times height
A=10 times 7
A=70 cm²
We can get the Circumference of a circle with the diameter by using the formula:
Circumference = Diameter * pie
Where, pie = 22/7 = 3.14
Hope this helps!
The chance of One heads occurring is 1/2.
The chance of the second occurring separately is 1/2 as well. Joint together, it is 1/2x1/2: which is 1/4.
So your answer is 1/4 chance
I hope this Helps!
