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IgorC [24]
3 years ago
10

Solve for x PLEASE HELP I've been stuck for about a hour on this

Mathematics
1 answer:
Naily [24]3 years ago
6 0

Answer:

C) 5

Step-by-step explanation:

As the horizontal lines are parallel, the ratio of the segments will be constant.

3/(3 + 4) = (x - 1)/14

3(14) = 7(x - 1)

  42 = 7x - 7

   7x = 35

     x = 5

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HELP ASAP PLZ HELP<br> I will give a brain list if it is right !!! <br> just help me plz
lilavasa [31]
Answer: A

Explanation:
First you have to write the model in an equation form.

6x+5=15

Subtract 5 from both sides

6x=10

Divide 6 from both sides

X=10/6

Simplify

X=5/3 or 1.67
8 0
3 years ago
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If tan x =1/2<br> find sin x<br> 2
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6 0
3 years ago
How many more unit tiles must be added to the function f(x)=x2−6x+1 in order to complete the square? 1 6 8 9
lawyer [7]

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4 0
3 years ago
Plz guys help i need asap<br> its part b im stuck
aleksklad [387]

Answer:

a.2nd quarter with 9 goals

b. 4.8 goals

c. 4 goals

Step-by-step explanation:

a. The mode is defined as the most appearing data point or the data point with the highest frequency..

From our data(for away goals):

  • 1st quarter-2
  • 2nd quarter-9
  • 3rd quarter-7
  • 4th quarter-4

Hence, the 2nd quarter has the mode for away goals with 9 goals.

b. Mean is defined as the average of a set of data points.

#We calculate the totals goals per quarter, sum over all quarters then divide by the number of games, 10:

\bar x=\frac{1}{n}\sum{x_i}\\1^{st }_g=Away+Home=5+2=7\\\\2^{nd}_g=Away+Home=4+9=13\\\\3^{rd}_g=Away+Home=8+7=15\\\\4^{th}_g=Away+Home=9+4=13\\\\\bar x=\frac{1}{n}\sum{x_i}=\frac{1}{10}(7+13+15+13)=4.8

Hence, the mean number of goals per quarter is 4.8 goals

c. To find the number of more home goals than away goals, we subtract from their summations as:

g_m=\sum{g_h}-\sum{g_a}\\\\=(5+4+8+9)-(2+9+7+4)\\\\=26-22\\\\=4

Hence, there are 4 more home goals than away goals.

4 0
3 years ago
I need help on finding an equation!?
Sedbober [7]

Your distance from Seattle after two hours of driving at 62 mph, from a starting point 38 miles east of Seattle, will be (38 + [62 mph][2 hr] ) miles, or 162 miles (east).

Your friend will be (20 + [65 mph][2 hrs] ) miles, or 150 miles south of Seattle.

Comparing 162 miles and 150 miles, we see that you will be further from Seattle than your friend after 2 hours.

After how many hours will you and your friend be the same distance from Seattle?  Equate 20 + [65 mph]t to 38 + [62 mph]t and solve the resulting equation for time, t:

20 + [65 mph]t  = 38 + [62 mph]t

Subtract [62 mph]t  from both sides of this equation, obtaining:

20 + [3 mph]t = 38.  Then [3 mph]t = 18, and t = 6 hours.

You and your friend will be the same distance from Seattle (but in different directions) after 6 hours.

7 0
3 years ago
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