Length of deck is 40 feet
<h3><u><em>Solution:</em></u></h3>
Sam wants the deck to have an overall perimeter of 60 feet
Perimeter of rectangular deck = 60 feet
Let "L" be the length of rectangle and "W" be the width of rectangle
Given that plans for a rectangular deck call for the width to be 10 feet less than the length
Width = length - 10
W = L - 10 ------ eqn 1
<em><u>The perimeter of rectangle is given as:</u></em>
perimeter of rectangle = 2(length + width)
Substituting the known values we get,
60 = 2(L + L - 10)
60 = 2(2L - 10)
60 = 4L - 20
80 = 4L
L = 20
Thus the length of deck is 20 feet
32=16x2=2x2x2x2x2=2^5
48=24*2=6x4x2=2x3x2x2x2
Pick the highest number that occurs. In this case it is 2. Now we have to see how many times it appears in both. It appears 5 times in 32 and 4 times in 48. 4 is the highest number of times it appears in the numbers so:
2^4=2x2x2x2=16
The Greatest Common Factor (GCF) of 32 and 48 is 16.
My teacher taught me to make an imaginary decimal and 0 at the beginning of the number and then move the decimal to the end of the number... idk that may be the wrong way to do it but you can try :/
Answer:
x = 2y + 1 + (z/2)
Step-by-step explanation:
Just manipulate the equation to isolate x.
