The area enclosed by the figure is 4533.48 square meters.
<u>Step-by-step explanation:</u>
Side length of the square = 42m
The semicircle is attached to each side of the square. So the diameter of the semicircle is the length of the square.
Radius of the semicircle = 21m
Area of the square = 42 x 42 = 1764 square meters
Area of 1 semicircle = π(21 x 21) /2
= (3.14) (441) /2
= 1384.74/2
= 692.37 square meters
Area of 4 semicircle = 4 x 692.37
= 2769.48 square meters
Total area = 1764 + 2769.48
= 4533.48 square meters
The area enclosed by the figure is 4533.48 square meters.
Answer:
B
Step-by-step explanation:
Answer:
The answer to your question is the first option
Step-by-step explanation:
Write the division
7x³ - 7x² + 6x +4 Result
x + 1 7x⁴ - 0x³ - 1x² + 10x + 15
-7x⁴ - 7x³
0 - 7x³ - 1x²
+ 7x³ +7x²
0 + 6x² + 10x
- 6x² - 6x
0 + 4x + 15
- 4x - 4
0 + 11 Remainder
Result = 7x³ - 7x² + 6x + 4 + 11 / x + 1
Answer:
After 4 days, the number of people attending both conferences be the same.
Step-by-step explanation:
We are given the following in the question:
Maths conference:
Number of people already signed = 7
Number of people who sign up each day = 2
Thus, the number of people who will sign up for maths conference in x days will be given by the linear function:
History conference:
Number of people already signed =11
Number of people who sign up each day = 1
Thus, the number of people who will sign up for maths conference in x days will be given by the linear function:
Both conference will have same number of people when
Thus, after 4 days, the number of people attending both conferences be the same.
