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lidiya [134]
3 years ago
10

What makes a trapezoid an isosceles trapezoid?

Mathematics
2 answers:
swat323 years ago
7 0
B. It’s bases are congruent

Explanation: A trapezoid is a quadrilateral with exactly one pair of parallel sides. In a trapezoid the parallel sides are called bases. A pair of angles that share a base as a common side are called a pair of base angles. A trapezoid with the two non-parallel sides the same length is called an isosceles trapezoid.
Romashka-Z-Leto [24]3 years ago
4 0

Answer:

  A.  Its legs are congruent.

Step-by-step explanation:

It is a parallelogram if ...

  • the bases are congruent,
  • opposite angles are congruent, or
  • the diagonals bisect each other.
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5/6 x 3/20 as a fraction
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Answer:

1/8

Step-by-step explanation:

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How can you determine if a triangle is a right triangle given the 3 side lengths?
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To know that a triangle is right angled triangle we will have to apply pythagoras theorem to verify it

Like length 3, 4 and 5 are leghts of right angled triangle

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What issue results from the combination of limited resources and unlimited wants?
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Read 2 more answers
If y=8 when x=4 find y when x=5
djyliett [7]

Answer:

y = 10 when x = 5

Step-by-step explanation:

When x = 4, y = 8

Simplify. Divide 4 from both x and y

x = 4/4 = 1

y = 8/4 = 2

when x = 1, y = 2

Next, solve for when x = 5. Mutliply 5 to both x and y

x = 1 * 5 = 5

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y = 10 when x = 5

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7 0
3 years ago
Read 2 more answers
Select ALL the correct answers.
Marina CMI [18]

Answer:

The median of A is the same as the median of B.

The interquartile range of B is greater than the interquartile range of A.

Step-by-step explanation:

Given that:

A = number of runs allowed in first 9 games

A = {1, 4, 2, 2, 3, 1, 1, 2, 1}

Rearranging A : 1, 1, 1, 1, 2, 2, 2, 3, 4

Median A = 1/2(n + 1) th term

Median A = 1/2(10) = 5th term = 2

Q1 of A = 1/4(10) = 2.5th term = (1 + 1)/ 2 = 1

Q3 of A = 3/4(10) = 7.5th term = (2+3)/2 = 2.5

Interquartile range = Q3 - Q1 = 2.5 - 1 = 1.5

Number of runs allowed in 10th game = 9

B = {1, 4, 2, 2, 3, 1, 1, 2, 1, 9}

Rearranging B = 1, 1, 1, 1, 2, 2, 2, 3, 4, 9

Median A = 1/2(n + 1) th term

Median A = 1/2(11) = 5.5th term = (2+2)/2 = 2

Q1 of A = 1/4(11) = 2.75th tetm = (1 + 1)/ 2 = 1

Q3 of A = 3/4(11) = 8.25th term = (3+4)/2 = 3.5

Interquartile range = Q3 - Q1 = 3.5 - 1 = 2.5

Median A = 2 ; median B = 2

IQR B = 2.5 ; IQR A = 1.5 ; IQR B > IQR A

7 0
2 years ago
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