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3 years ago

9

Los Angeles is about 385 miles fr San Francisco. How far apart would the cities be on a map with scale of 1 in.= 25mi? If necess

ary, round to the nearest hundredth

1 answer:

antiseptic1488 [7]3 years ago

5 0

385 / 25 = 15.4

Answer 15.4 in

Hope this helped!

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Someone help me please thanks

Svet_ta [14]

About 6 ;) ............

8 0

3 years ago

When Belinda asked him to what pages his book was opened, he replied that the product of the facing pages was 87,912. To what pa

Liono4ka [1.6K]

Answer:

His book was opened at Page no.296 and Page no.297

Step-by-step explanation:

Let the page number of one page be x

Page number of page facing page no. x = x+1

We are given that the product of the facing pages was 87,912.

So, x(x+1)=87912

$x^2+x=87912$

$x^2+x-87912=0$

$x^2-296x+297x-87912=0$

$x(x-296)+297(x-296)=0$

(x+297)(x-296)=0

x=296,-297

Since Page no. cannot be negative

So, x=296

x+1=296+1=297

So, his book was opened at Page no.296 and Page no.297

5 0

3 years ago

Find the slope of each line and then determine if the lines are parallel, perpendicular or neither. If a value is not an integer

Aleonysh [2.5K]

As given by the question

There are given that the point of two-line

$\begin{gathered} (1,\text{ 7) and (5, 5)} \\ (-1,\text{ -3) and (1, 1)} \end{gathered}$

Now,

From the condition of a parallel and perpendicular line

If the slopes are equal then the lines are parallel

If the slopes are negative reciprocal then the lines are perpendicular

If the slopes are neither of the above are true then lines are neither

Then,

First, find the slope of both of line

So,

For first-line, from the formula of slope

$\begin{gathered} m_1=\frac{y_2-y_1}{x_2-x_1} \\ m_1=\frac{5_{}-7_{}}{5_{}-1_{}} \\ m_1=-\frac{2}{4} \\ m_1=-\frac{1}{2} \end{gathered}$

Now,

For second-line,

$\begin{gathered} m_1=\frac{y_2-y_1}{x_2-x_1} \\ m_1=\frac{1_{}-(-3)_{}}{1-(-1)_{}} \\ m_1=\frac{4}{2} \\ m_1=2 \end{gathered}$

The given result of the slope is negative reciprocal because

$\begin{gathered} -\frac{1}{2}=-(-\frac{2}{1}) \\ -\frac{1}{2}=2 \end{gathered}$

Hence, the slope of line1 is -1/2, and slope of line2 is 2 and the lines are perpendicular.

5 0

1 year ago

Jika 5log2 = x dan 5log6 = y, maka nilai 4log150 adalah

icang [17]

Menjawab:

y + 2x

Penjelasan langkah demi langkah:

Menulis ulang pertanyaannya

4log5 = x

4log 6 = y

4 log 150 = 4log (2 * 3 * 5 * 5)

= 4log 6 + 4log 5 + 4log 5

Substrat

= y + x + x

= y + 2x

Oleh karena itu ekspresi yang dibutuhkan adalah y + 2x

7 0

3 years ago

Find the product of z1 and z2, where z1 = 7(cos 40° + i sin 40°) and z2 = 6(cos 145° + i sin 145°).

Oduvanchick [21]

For two complex numbers $z_1=re^{i\theta}=r(\cos\theta+i\sin\theta)$ and $z_2=se^{i\varphi}=s(\cos\varphi+i\sin\varphi)$ , the product is

$z_1z_2=rse^{i(\theta+\varphi)}=rs(\cos(\theta+\varphi)+i\sin(\theta+\varphi))$

That is, you multiply the moduli and add the arguments. You have $z_1=7e^{i40^\circ}$ and $z_2=6e^{i145^\circ}$ , so the product is

$z_1z_2=7\times6(\cos(40^\circ+145^\circ)+i\sin(40^\circ+145^\circ)=42(\cos185^\circ+i\sin185^\circ)=42e^{i185^\circ}$

3 0

3 years ago

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