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Elodia [21]
3 years ago
9

Help me ASAP!!!!!!!!!!!!!:)

Mathematics
2 answers:
Mars2501 [29]3 years ago
8 0

Answer:

-18y=1

X will be eliminated

Step-by-step explanation:

-5x-9y=3

5x-9y=-2

—------------

-18y=1

y=-1/18

kenny6666 [7]3 years ago
5 0

Answer:

I think it is wrong because it is unlike term

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Write the slip-intercept form of the equation of the line described
kompoz [17]

Answer:

1) y=⅚x -2⅓

2) y=8/3x -5

Step-by-step explanation:

<u>Point-slope form:</u>

y=mx+c, where m is the gradient and c is the y-intercept.

Parallel lines have the same gradient.

Gradient of given line= \frac{5}{6}

Thus, m=⅚

Susbt. m=⅚ into the equation,

y= ⅚x +c

Since the line passes through the point (4, 1), (4, 1) must satisfy the equation. Thus, substitute (4, 1) into the equation to find c.

When x=4, y=1,

1= ⅚(4) +c

1 =  \frac{20}{6}  + c \\ c = 1 -  \frac{20}{6}  \\ c = 1 - 3 \frac{1}{3}  \\ c =  - 2 \frac{1}{3}

Thus the equation of the line is y =  \frac{5}{6} x - 2 \frac{1}{3}.

The gradients of perpendicular lines= -1.

Gradient of given line= -⅜

-⅜(gradient of line)= -1

gradient of line

= -1 ÷ (-⅜)

= -1 ×(-8/3)

= \frac{8}{3}

y =  \frac{8}{3} x + c

When x=3, y=3,

3 =  \frac{8}{3} (3) + c \\ 3 = 8 + c \\ c = 3 - 8 \\ c =  - 5

Thus the equation of the line is y =  \frac{8}{3} x - 5.

4 0
3 years ago
PLEASE HELP!!!!
algol13
Sin(theta)=-15/17
cos(theta)=8/17
tan(theta)=-15/8
csc(theta)=-17/15
sec(theta)=17/8
cot(theta)=-8/15
Hope this helps
4 0
2 years ago
Read 2 more answers
Question:4x²-9 <br>answer:​
statuscvo [17]

Step-by-step explanation:

4x^2-9

=(2x)^2 -3^2

=(2x+3) (2x-3)

Hope this helps you.

3 0
2 years ago
A man deposited $ 800 in his account at a bank which offers 6% simple interest per annum. How much interest would he receive on
strojnjashka [21]

Answer:

The answer is Rs.43,200.

5 0
3 years ago
2. Trey measured the mass of some pebbles What is the combined mass of the pebbles that are 4 1/2 grams or more?
Romashka-Z-Leto [24]

Answer:

40

Step-by-step explanation:

3 0
3 years ago
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