Question

Scores on Ms. Nash's test have a mean of 64 and a standard deviation of 9. Steve has a score of 52. Convert Steve's score to a z-score. (Round to two decimal places if necessary.)
a. 58.2
b. –1.33
c. 1.33
d. –2

Answer 1

Answer:

b. –1.33

Step-by-step explanation:

The z-score measures how many standard deviations a score X is above or below the mean.

It is given by the following formula:

$Z = \frac{X - \mu}{\sigma}$

In which $\mu$ is the mean and $\sigma$ is the standard deviation.

In this problem, we have that:

$\mu = 64, \sigma = 9, X = 52$. We have to find Z

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{52 - 64}{9}$

$Z = -1.33$

So the correct answer is:

b. –1.33