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AveGali [126]
3 years ago
11

Omar is born weighing 8 pounds,3 ounces.The doctor says he should gain a about 5 ounces each week for the next 4 weeks.How much

should Omar weigh after 4 weeks?
Mathematics
2 answers:
hoa [83]3 years ago
6 0
Start weight- 8.03
week 1 - 8.8
week 2 - 8.13
week 3 - 9.03
week 4 - 9.08

So, the Omar should weigh 9 pounds 8 ounces by the end of 4 weeks.

I hope this helped!
Serjik [45]3 years ago
4 0

Answer: find it out yourself  lol gimme ur computer

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A random sample of 11 fields of rye has a mean yield of 20.1 bushels per acre and standard deviation of 7.66 bushels per acre. D
Lady bird [3.3K]

Answer:

17.1≤x≤23.1

Step-by-step explanation:

The formula for calculating the confidence interval is expressed as;

CI = x ± z*s/√n

x is the mean yield = 20.1

z is the 80% z-score = 1.282

s is the standard deviation = 7.66

n is the sample size =  11

Substitute

CI = 20.1 ± 1.282*7.66/√11

CI = 20.1 ± 1.282*7.66/3.3166

CI = 20.1 ± 1.282*2.3095

CI =  20.1 ±2.9609

CI = (20.1-2.9609, 20.1+2.9609)

CI = (17.139, 23.0609)

hence the required confidence interval to 1dp is 17.1≤x≤23.1

8 0
3 years ago
20 POINTS!!!
notka56 [123]

\dfrac{2}{\sqrt3\cos x+\sin x}=\sec\left(\dfrac{\pi}{6}-x\right)\\\\\dfrac{2}{\sqrt3\cos x+\sin x}=\dfrac{1}{\cos\left(\dfrac{\pi}{6}-x\right)}\ \ \ \ \ (*)\\----------------\\\\\cos\left(\dfrac{\pi}{6}-x\right)\ \ \ \ |\text{use}\ \cos(x-y)=\cos x\cos y+\sin x\sin y\\\\=\cos\dfrac{\pi}{6}\cos x+\sin\dfrac{\pi}{6}\sin x=\dfrac{\sqrt3}{2}\cos x+\dfrac{1}{2}\sin x=\dfrac{\sqrt3\cos x+\sin x}{2}\\------------------------------

(*)\\R_s=\sec\left(\dfrac{\pi}{6}-x\right)=\dfrac{1}{\cos\left(\dfrac{\pi}{6}-x\right)}=\dfrac{1}{\dfrac{\sqrt3\cos x+\sin x}{2}}\\\\=\dfrac{2}{\sqrt3\cos x+\sin x}=L_s

6 0
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Andre45 [30]

Answer:

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Step-by-step explanation:

7 0
3 years ago
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Find the shaded area
My name is Ann [436]

Answer:

113.1in²

Step-by-step explanation:

The answer for this question will be 113.1in²

As we know the diameter that is 12 inches.

Thats how we got the area for this question.

Hope this helps

6 0
3 years ago
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Please help im stuck
agasfer [191]

Answer:

Area of field = 10 cm²

Step-by-step explanation:

Given field is a trapezium;

Parallel sides of given field are; 1¹/₂ cm and 3¹/₂ cm

Height of trapezium = 4 cm

Find:

Area of field

Computation:

Area of field = Area of trapezium

Area of trapezium = [Sum of Parallel sides / 2][h]

Area of field = [(1¹/₂ + 3¹/₂) / 2][4]

Area of field = [(5) / 2][4]

Area of field = [2.5][4]

Area of field = 10 cm²

8 0
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