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Rama09 [41]
3 years ago
11

Which is NOT true about a protostar?

Physics
1 answer:
jek_recluse [69]3 years ago
4 0

Answer:

D

Explanation:

D it generates pressure by fusing hydrogen.

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A ball held 2.0 meters above the floor has 59 joules of potential energy the bald mass is about
PilotLPTM [1.2K]

Answer:

Mass of ball = 3.0102 Kg.

Explanation:

Potential energy at height h is given by

PE = mgh

where m is the mass of the body

g is the the acceleration due to gravity whose value is 9.8 m/s^2

h is the height from surface level

PE is potential energy

In the problem given h = 2 meters

PE = 59 joules

59 = m*9.8*2

=> m = 59/9.8*2 = 3.0102 Kg

Thus, mass of ball is 3.0102 Kg.

4 0
4 years ago
PLEASE HELP!! ITS URGENT!!!​
Natasha2012 [34]

Answer:

F = 800 [N]

Explanation:

To be able to calculate this problem we must use the principle of momentum before and after the impact of the hammer.

We must summarize that after the impact the hammer does not move, therefore its speed is zero. In this way, we can propose the following equation.

ΣPbefore = ΣPafter

(m_{1}*v_{1}) - F*t = (m_{1}*v_{2})

where:

m₁ = mass of the hammer = 0.15 [m/s]

v₁ = velocity of the hammer = 8 [m/s]

F = force [N] (units of Newtons)

t = time = 0.0015 [s]

v₂ = velocity of the hammer after the impact = 0

(0.15*8)-(F*0.0015) = (0.15*0)\\F*0.0015 = 0.15*8\\F = 1.2/(0.0015)\\F = 800 [N]

Note: The force is taken as negative since it is exerted by the nail on the hammer and this force is directed in the opposite direction to the movement of the hammer.

6 0
3 years ago
How might scientists study something that they cannot observe directly?
yarga [219]

Answer:

The sun

Explanation:

if they get too close even the heat that radiates of of it would burn you or give sunburn bad and the sun is a shining ball of energy it is way to hot for a human to get close

8 0
3 years ago
Technetium (Tc; Z = 43) is a synthetic element used as a radioactive tracer in medical studies. A Tc atom emits a beta particle
LenKa [72]

Answer : The de-Broglie wavelength of this electron, 0.101\AA

Explanation :

The formula used for kinetic energy is,

K.E=\frac{1}{2}mv^2        ..........(1)

According to de-Broglie, the expression for wavelength is,

\lambda=\frac{h}{mv}

or,

v=\frac{h}{m\lambda}      ...........(2)

Now put the equation (2) in equation (1), we get:

\lambda=\frac{h}{\sqrt{2\times m\times K.E}}  ...........(3)

where,

\lambda = wavelength = ?

h = Planck's constant = 6.626\times 10^{-34}Js

m = mass of electron = 9.11\times 10^{-31}Kg

K.E = kinetic energy = 4.71\times 10^{-15}J

Now put all the given values in the above formula (3), we get:

\lambda=\frac{6.626\times 10^{-34}Js}{\sqrt{2\times 9.11\times 10^{-31}Kg\times 4.71\times 10^{-15}J}}

\lambda=1.0115\times 10^{-11}m=0.101\AA

conversion used : (1\AA=10^{-10}m)

Therefore, the de-Broglie wavelength of this electron, 0.101\AA

7 0
3 years ago
Which has the least potential energy
makvit [3.9K]

Answer:

The plasma state would have the least potential energy and the greatest kinetic energy.

Explanation:

i just took the test and i go it right

4 0
3 years ago
Read 2 more answers
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