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maks197457 [2]
3 years ago
6

When a nerve cell depolarizes, charge is transferred across the cell membrane, changing the potential difference. For a typical

nerve cell, 9.0pC of charge flows in a time of 0.5ms. What is the average current
Physics
2 answers:
igomit [66]3 years ago
6 0

Answer:

1.8nA

Explanation:

I = dq/dt

I = 9.0 × 10 ^-12 / 0.5 × 10^-3

I = 1.8 × 10× 10^-8

I = 1.8nA

SCORPION-xisa [38]3 years ago
5 0

Answer:

18aN

Explanation:

To calculate the average current, we need to know the the formal for it. The formula for average current is given by;

I = dq/dt

= 9×10^(-12)C÷0.5×10^(-3)S

= 1.8×10^(-9)

= 18aN

Therefore, average current when calculated is gotten as 18aN

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An electron of mass 9.11 1031 kg has an initial speed of 3.00 105 m/s. It travels in a straight line, and its speed increases to
elena55 [62]

Explanation:

It is given that,

Mass of an electron, m=9.11\times 10^{-31}\ kg

Initial speed of the electron, u=3\times 10^5\ m/s

Final speed of the electron, v=7\times 10^5\ m/s

Distance, d = 5 cm = 0.05 m

(a) The acceleration of the electron is calculated using the third equation of motion as :

a=\dfrac{v^2-u^2}{2d}

a=\dfrac{(7\times 10^5)^2-(3\times 10^5)^2}{2\times 0.05}

a=4\times 10^{12}\ m/s^2

Force exerted on the electron is given by :

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F=3.64\times 10^{-18}\ N

(b) Let W is the weight of the electron. It can be calculated as :

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W=9.11\times 10^{-31}\times 9.8

W=8.92\times 10^{-30}\ N

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\dfrac{F}{W}=4.08\times 10^{11}

Hence, this is the required solution.

8 0
4 years ago
You place a box weighing 289.9 N on an inclined plane that makes a 35.9 degree angle with the horizontal. Compute the component
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Answer:

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Explanation:

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mg is 289.9, as that is the weight. θ is 35.9

Fgpar = 289.9sin35.9

Fgparallel =  170N

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