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1 answer:
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Explanation:
It is given that,
Work done, W = 240 J
Heat removed, Q = 610 J
(a) The refrigerator's coefficient of performance is given by :
COF = 2.54
(b) Let Q' is the heat per cycle is exhausted to the kitchen. It is given by :
Q' = Q + W
Q' = 610 + 240
Q' = 850 J
Hence, this is the required solution.
The body moves at a velocity of 1.62m/s after the bullet emerges.
<h3>Given:</h3>Mass of bullet, = 22g
= 0.022 kg
Mass of the block, = 1.9 kg
Velocity of bullet , = 265 m/s
According to the law of collision which states that the momentum of the body before the collision is equal to the momentum of the body after the collision.
After penetration;
The formula for calculating the collision of a body is expressed as:
p = mv
m is the mass of the body
v is the velocity of the body
∴ Momentum before = Momentum after
Substitute the given parameters into the formula as shown:
Therefore, It moves with a velocity of 1.62 m/s.
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