A Chevy Camaro drives straight off the top level off a parking garage at 13 m/s. If the car landed 90 meters away from the base
of the parking garage, how high (height) was the top level?
a200.64
b234.64
c34.64
d134.64
1 answer:
Answer:
234.64 m
Explanation:
Using the formula for calculating range;
Range R = u√2H/g
u is the speed = 13m/s
H is the maximum height
g is the acceleration due to gravity = 9,8m/s²
R = 90m
Get the maximum height;
90 = 13√2H/9.8
90/13 = √2H/9.8
6.923 = √2H/9.8
square both sides
6.923² = 2H/9.8
469.698 = 2H
H = 469.698/2
H = 234.64
Hence the top level was 234.64 m high.
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