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Alchen [17]
3 years ago
9

Which equation can be used to solve for b?

Mathematics
1 answer:
erik [133]3 years ago
6 0

Answer:8tan(30)

Step-by-step explanation:

It is right angle triangle. The given data includes angle 30 and the side "b" infront i.e. perpendicular and the base 8ft.

So tan(30)=b/8

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How can you use a number line to model and compare positive and negative rational numbers
kifflom [539]
Hello There!

Well, as you know a number line is a line where you can place numbers with different spaces between them. It can be used to compare them in distance (the further apart they are on the line, the greater the difference between the two numbers)

Hope This Helps You!
Good Luck :) 

- Hannah ❤
6 0
4 years ago
Please help! Need answer ASAP!
Umnica [9.8K]

Answer:

Step-by-step explanation:

A) identical triangles PSR and PSQ

B) in the given triangle PQR angle P is 90 degrees and PS is perpendicular on QR.  so the angle PSR and angle PSQ is 90 degrees also angles RPS , SPQ are 45 degrees . hence when two angles of a triangle are 90 and 45 degrees.  the third is also 45 degrees. when the three angles of two triangles are equal they are said to be similar

C) the triangle PSR is a isosceles triangle therfore the two sides of the two oposite equal angles must be equal. if RS=4  then SP=4 as well the sides opposite to 45 degrees angles. the third side can be found by using the formula

c²=a²+b²

c²=4²+4²=16+16=32

c=√32=√16*2=4√2

4 0
3 years ago
Finding the slope of (-2,3) and (2,-3)
Ne4ueva [31]

Answer:

Slope- m=-3/2

Step-by-step explanation:

7 0
3 years ago
Find the mean for the given set of data.<br> 18, 15, 22, 18, 25, 19, 23<br> 20
cluponka [151]

Answer: 20

Step-by-step explanation:

You find the mean by adding up all the numbers in a data set, then dividing by the number added.

18 + 15 + 22 + 18 + 25 + 19 + 23 + 20 = 160

We added 8 numbers together, so we divide 160 by 8

160/8 = 20

3 0
3 years ago
Read 2 more answers
An interior automotive supplier places several electrical wires in a harness.Apull test measures the force required to pull spli
oksano4ka [1.4K]

Answer:

a) For this case we can use the following R code to construct the qq plot

> data<-c(28.8, 24.4, 30.1, 25.6, 26.4, 23.9, 22.1, 22.5, 27.6, 28.1, 20.8, 27.7, 24.4, 25.1, 24.6, 26.3, 28.2, 22.2, 26.3, 24.4)

# The above line is in order to store the data in a vector

> qqnorm(data, pch = 1, frame = FALSE)

# The line above is in order to calculate the quantiles from the data assumin Normal distribution

> qqline(data, col = "steelblue", lwd = 2)

# The line above is in order to put a line for the theoretical dsitribution

The result is on the figure attached.

b) For this case as we can see on the figure attached the calculated quantiles are not far from the theorical quantiles given byt the straaigth blue line so then we can conclude that the distribution seems to be normal.

Step-by-step explanation:

For this case we have the following data:

28.8, 24.4, 30.1, 25.6, 26.4, 23.9, 22.1, 22.5, 27.6, 28.1, 20.8, 27.7, 24.4, 25.1, 24.6, 26.3, 28.2, 22.2, 26.3, 24.4

The quantile-quantile or q-q plot is a graphical procedure in order to check the validity of a distributional assumption for a data set. We just need to calculate "the theoretically expected value for each data point based on the distribution in question".

If the values are asusted to the assumed distribution, we will see that "the points on the q-q plot will fall approximately on a straight line"

For this case our distribution assumed is normal.

Part a

For this case we can use the following R code to construct the qq plot

> data<-c(28.8, 24.4, 30.1, 25.6, 26.4, 23.9, 22.1, 22.5, 27.6, 28.1, 20.8, 27.7, 24.4, 25.1, 24.6, 26.3, 28.2, 22.2, 26.3, 24.4)

# The above line is in order to store the data in a vector

> qqnorm(data, pch = 1, frame = FALSE)

# The line above is in order to calculate the quantiles from the data assuming Normal distribution (0,1)

> qqline(data, col = "steelblue", lwd = 2)

# The line above is in order to put a line for the theoretical distribution

The result is on the figure attached.

Part b

For this case as we can see on the figure attached the calculated quantiles are not far from the theorical quantiles given byt the straaigth blue line so then we can conclude that the distribution seems to be normal.

4 0
4 years ago
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