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scoundrel [369]
3 years ago
5

2. José is using 12 brown tiles and

Mathematics
1 answer:
Karolina [17]3 years ago
3 0

Answer:

12:20

Step-by-step explanation:

your trying to find the ratio to brown tiles to one section and theirs 12 brown tiles per section so you would start off with 12. and to find how many tiles would be in each section you would have to add 8 and 12 and you would end up with 20 which the number of tiles in each section

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Help plz i will give brainist
Lemur [1.5K]

Answer:

Hes correct with number 1 aka answer A

Step-by-step explanation:

Its talking abt in the middle hes suppose to divide the six bc at the end it will have 1/8-1/8-1/8 and 2 negatives make a positive meaning it would be 2/8-1/8=1/8 there for number 1 aka A is right btw i want brainiest for explanation thx :)

4 0
3 years ago
I don’t know the answer
anastassius [24]
I THINK IT IS B

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3 years ago
Find a nonzero vector orthogonal to the plane through the points: ????=(0,0,1), ????=(−2,3,4), ????=(−2,2,0).
ser-zykov [4K]

Answer:

The nonzero vector orthogonal to the plane is <-9,-8,2>.

Step-by-step explanation:

Consider the given points are P=(0,0,1), Q=(−2,3,4), R=(−2,2,0).

\overrightarrow {PQ}==

\overrightarrow {PR}==

The nonzero vector orthogonal to the plane through the points P,Q, and R is

\overrightarrow n=\overrightarrow {PQ}\times \overrightarrow {PR}

\overrightarrow n=\det \begin{pmatrix}i&j&k\\ \:\:\:\:\:-2&3&3\\ \:\:\:\:\:-2&2&-1\end{pmatrix}

Expand along row 1.

\overrightarrow n=i\det \begin{pmatrix}3&3\\ 2&-1\end{pmatrix}-j\det \begin{pmatrix}-2&3\\ -2&-1\end{pmatrix}+k\det \begin{pmatrix}-2&3\\ -2&2\end{pmatrix}

\overrightarrow n=i(-9)-j(8)+k(2)

\overrightarrow n=-9i-8j+2k

\overrightarrow n=

Therefore, the nonzero vector orthogonal to the plane is <-9,-8,2>.

8 0
4 years ago
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Yakvenalex [24]
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