The statement "The domain of (fg)(x) consists of the numbers x that are in the domains of both f and g" is FALSE.
Domain is the values of x in the function represented by y=f(x), for which y exists.
THe given statement is "The domain of (fg)(x) consists of the numbers x that are in the domains of both f and g".
Now we assume the
and 
So here since g(x) is a polynomial function so it exists for all real x.
<em> </em>does not exists when
, so the domain of f(x) is given by all real x except 6.
Now,

So now (fg)(x) does not exists when x=4, the domain of (fg)(x) consists of all real value of x except 4.
But domain of both f(x) and g(x) consists of the value x=4.
Hence the statement is not TRUE universarily.
Thus the given statement about the composition of function is FALSE.
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total surface area Stot = 1180 in2
lateral surface area Slat = 920 in2
top surface area Stop = 130 in2
bottom surface area Sbot = 130 in2
<span>simplified would be
</span><span>
2(x + 3)+ 8 + 5(x - 2) + 4x + 3
= 2x + 6 + 8 +5x -10 + 4x +3
= (</span>2x + 5x +4x ) + (6 + 8 -10 + 3)
=11x + 7
A line parallel to y = 2/3 x - 5 will have a slope of 2/3.
The equation of a line passing through (-6, -1) with a slope of 2/3 is
y - (-1) = 2/3 (x - (-6))
The degree is nothing more than the highest exponent value. The degree of this expression would be 5