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MatroZZZ [7]
3 years ago
7

CRACK the CODE

Mathematics
1 answer:
Studentka2010 [4]3 years ago
4 0

Answer:

yea i dont know this one bro

Step-by-step explanation:

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Joshira makes and sells crafts.
Maksim231197 [3]

Answer: 6

Step-by-step explanation:

i think joshira makes 6 item in 8 hours.

i got my answer by multiplying 3/4 with 8

7 0
3 years ago
Read 2 more answers
last year 950 people attended a towns annual parade. this year 1,520 people attended what was the percent increase in attendance
inessss [21]
<span>To calculate the percentage increase: First: work out the difference (increase) between the two numbers you are comparing. Then: divide the increase by the original number and multiply the answer by 100.
1520-950=570
570÷950= 0.6 × 100=60%


</span>
7 0
3 years ago
Help me pls don’t put random
Vladimir [108]
I think it’s A
Sorry if I’m wrong
4 0
3 years ago
Read 2 more answers
Evaluate the geometric series. Round to the nearest hundredth. Please help me!!!
kari74 [83]

Answer:

62.34

Step-by-step explanation:

Substitute n = 0 to n = 5 into the expression and sum the terms, that is

3 [ (\frac{3}{2}) ^{0}  + (\frac{3}{2}) ^{1} + (\frac{3}{2}) ^{2} + (\frac{3}{2}) ^{3} + (\frac{3}{2}) ^{4} + (\frac{3}{2}) ^{5} ]

= 3 [ 1 + \frac{3}{2} + \frac{9}{4} + \frac{27}{8} + \frac{81}{16} + \frac{243}{32} ]

= 3( \frac{665}{32} )

= 3 × 20.781

= 62.34 ( to the nearest hundredth )

5 0
4 years ago
The population of Henderson City was 3,381,000 in 1994, and is growing at an annual rate 1.8%
liq [111]
<h2>In the year 2000, population will be 3,762,979 approximately. Population will double by the year 2033.</h2>

Step-by-step explanation:

   Given that the population grows every year at the same rate( 1.8% ), we can model the population similar to a compound Interest problem.

   From 1994, every subsequent year the new population is obtained by multiplying the previous years' population by \frac{100+1.8}{100} = \frac{101.8}{100}.

   So, the population in the year t can be given by P(t)=3,381,000\textrm{x}(\frac{101.8}{100})^{(t-1994)}

   Population in the year 2000 = 3,381,000\textrm{x}(\frac{101.8}{100})^{6}=3,762,979.38

Population in year 2000 = 3,762,979

   Let us assume population doubles by year y.

2\textrm{x}(3,381,000)=(3,381,000)\textrm{x}(\frac{101.8}{100})^{(y-1994)}

log_{10}2=(y-1994)log_{10}(\frac{101.8}{100})

y-1994=\frac{log_{10}2}{log_{10}1.018}=38.8537

y≈2033

∴ By 2033, the population doubles.

4 0
3 years ago
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