Answer:
d. cross-functional strategies
Explanation:
In an organisation, for the proper running of all the departments or functions, proper communications and coordination is required. So implementing the cross-functional strategies can succeed when all the functional areas of the organisation are properly coordinated with each other. And by implementing these strategies we can trace out the business strategy with supporting of all functional areas. These are useful to place all functional strategies properly.
Thus the answer is d. cross-functional strategies.
Answer:
$0.25
Explanation:
The marginal cost of the sixth pencil is given by the difference in total cost of purchasing 6 pencils from the cost of purchasing 5 pencils. That is, the change in cost caused by the addition of the sixth unit of output:
The marginal cost of the sixth pencil is $0.25
Knowing your income will help you create a budget that allows to pay for living expenses
Answer:
- <em>As explained below, given that the score of the person is among the 0.03125 fraction of the best applicants, </em><u><em>he can count on getting one of the jobs.</em></u>
<em></em>
Explanation:
The hint is to use <em>Chebyshev’s Theorem.</em>
Chebyshev’s Theorem applies to any data set, even if it is not bell-shaped.
Chebyshev’s Theorem states that at least 1−1/k² of the data lie within k standard deviations of the mean.
For this sample you have:
- mean: 60
- standard deviation: 6
- score: 84
The number of standard deviations that 84 is from the mean is:
- k = (score - mean) / standar deviation
- k = (84 - 60) / 6 = 24 / 6 = 4
Thus, the score of the person is 4 standard deviations above the mean.
How good is that?
Chebyshev’s Theorem states that at least 1−1/k² of the data lie within k standard deviations of the mean. For k = 4, that is:
- 1 - 1/4² = 1 - 1/16 = 0.9375
- That means that half of 1 - 0.9375 are above k = 4: 0.03125
- Then, 1 - 0.03125 are below k = 4: 0.96875
Since there are 70 positions and 1,000 aplicants, 70/1,000 = 0.07. The compnay should select the best 0.07 of the applicants.
Given that the score of the person is among the 0.03125 upper fraction of the applicants, this person can count of geting one of the jobs.
