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2 years ago

Perform the following Operations on fraction 1/5÷4/5=?

Mathematics

1 answer:

kicyunya [14]2 years ago

4 0

Answer: 1/ 4

Step-by-step explanation:

1/5 x 5/ 4 reduce the numbers with the greatest common factor 5

1/4

1 is ontop 4 is in the bottom 1/4

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What is the Y value of the point that Partitions the directed line segment A.B. into a 1:3 ratio

xenn [34]

Answer:

y = 5

Step-by-step explanation:

AB = | 8 - (- 4) | = | 12 |= 12

Divide 12 by the sum of the parts of the ratio, 1 + 3 = 4

12 ÷ 4 = 3

Thus

y = 8 - 3 = 5

5 0

2 years ago

What is the coefficient of the expression:<br> 3n+4

umka2103 [35]

Answer:

The coefficient is 3, the number right before the variable.

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3 years ago

Read 2 more answers

1.Find the compound interest on Rs25000 for 3 years at 10% per annum ,Compounded annually.

LekaFEV [45]

Answer:

The compound interest is Rs8275

Step-by-step explanation:

The rule of the compound interest is A = P $(1+\frac{r}{n})^{nr}$ , where

A is the new amount

P is the initial amount

r is the interest rate in decimal

n is the number of periods

t is the time

The interest I = A - P

∵ The amount of investment is Rs25000 for 3 years

∴ P = 25000

∴ t = 3

∵ The rate of interest is 10% per annum, compounded annually

∴ r = 10% = 10 ÷ 100 = 0.1

∴ n = 1 ⇒ compounded annually

→ Substitute these value in the 1st rule above to find the new amount

∵ A = 25000 $(1+\frac{0.1}{1})^{1(3)}$

∴ A = 25000 $(1.1)^{3}$

∴ A = Rs33275

→ Use the 2nd rule above to find the interest

∵ I = 33275 - 25000

∴ I = 8275

∴ The compound interest is Rs8275

6 0

2 years ago

write an equation for a function at has a graph with the given characteristics. the shape of y=|x| is reflected across the y-axi

Luba_88 [7]

Refrection across the y-axis changes the function to y = |-x|.
Vertical stretch by a factor of 1.5 changes the graph to y = 1.5|-x|
Shifting the graph by 4 units downward changes the graph to y = 1.5|-x| - 4

Required equation is y = 1.5|-x| - 4

6 0

3 years ago

Select the curve generated by the parametric equations. Indicate with an arrow the direction in which the curve is traced as t i

bixtya [17]

Answer:

length of the curve = 8

Step-by-step explanation:

Given parametric equations are x = t + sin(t) and y = cos(t) and given interval is

−π ≤ t ≤ π

Given data the arrow the direction in which the curve is traces means

the length of the curve of the given parametric equations.

The formula of length of the curve is

$\int\limits^a_b {\sqrt{\frac{(dx}{dt}) ^{2}+(\frac{dy}{dt}) ^2 } } \, dx$

Given limits values are −π ≤ t ≤ π

x = t + sin(t) ...….. (1)

y = cos(t).......(2)

differentiating equation (1) with respective to 'x'

$\frac{dx}{dt} = 1+cost$

differentiating equation (2) with respective to 'y'

$\frac{dy}{dt} = -sint$

The length of curve is

$\int\limits^\pi_\pi {\sqrt{(1+cost)^{2}+(-sint)^2 } } \, dt$

$\int\limits^\pi_\pi \, {\sqrt{(1+cost)^{2}+2cost+(sint)^2 } } \, dt$

on simplification , we get

here using sin^2(t) +cos^2(t) =1 and after simplification , we get

$\int\limits^\pi_\pi \, {\sqrt{(2+2cost } } \, dt$

$\sqrt{2} \int\limits^\pi_\pi \, {\sqrt{(1+1cost } } \, dt$

again using formula, 1+cost = 2cos^2(t/2)

$\sqrt{2} \int\limits^\pi _\pi {\sqrt{2cos^2\frac{t}{2} } } \, dt$

Taking common $\sqrt{2}$ we get ,

$\sqrt{2}\sqrt{2} \int\limits^\pi _\pi ( {\sqrt{cos^2\frac{t}{2} } } \, dt$

$2(\int\limits^\pi _\pi {cos\frac{t}{2} } \, dt$

$2(\frac{sin(\frac{t}{2} }{\frac{t}{2} } )^{\pi } _{-\pi }$

length of curve = $4(sin(\frac{\pi }{2} )- sin(\frac{-\pi }{2} ))$

length of the curve is = 4(1+1) = 8

<u>conclusion</u>:-

The arrow of the direction or the length of curve = 8

7 0

3 years ago

Perform the following Operations on fraction 1/5÷4/5=?​

Perform the following Operations on fraction 1/5÷4/5=?