Help... Jordan earns five dollars per hour babysitting. Each week he babysits six hours during the week, in four hours on the we
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Let P be the population proportion, p be the sample proportion, n be the sample size.
A manufacturer claims that fewer than 6% of its fax machines are defective. It means P=0.06
Sample size n=97 and sample proportion p=0.05
The hypothesis to be tested is
H0: P ≥ 0.06 V/s Ha: P < 0.06
Here the hypothesis for testing population proportion we use z test statistics. Z test statistics is give by
Z =
Where p =sample proportion = 0.05
p0 = hypothesized proportion value =0.06
Using given values into test statistics we get
Z =
Z = -0.41
The p-value for left tailed alternative hypothesis is given by
P-value = P(z < z cal)
where zcal = Z test statistics value
Here zcal = -0.41
P-value = P(Z < -0.41)
Using z score table to find probability below z=-0.41
P-value = 0.3409
P-value for testing the given claim is 0.3409
