The final temperature of the block of brass with a mass of 30.6 g at 87.4°C is 30.82°C.
SPECIFIC HEAT CAPACITY:
- The amount of heat absorbed or released by a substance can be calculated using the following formula:
- (m × c × ∆T) water = - (m × c × ∆T) metal
According to this question;
METAL:
- m = 30.6g
- c = 0.380 J/g°C
- ∆T = T - 87.4°C
WATER:
- m = 62.3g
- c = 4.184J/g°C
- ∆T = T - 28.3°C
- 62.3 × 4.184 × (T - 28.3) = - {30.6 × 0.380 × (T - 87.4)}
- 260.7T - 7376.8 = - {11.63T - 1016.3}
- 260.7T - 7376.8 = -11.63T + 1016.3
- 260.7T + 11.63T = 1016.3 + 7376.8
- Therefore, the final temperature of the block of brass with a mass of 30.6 g at 87.4°C is 30.82°C.
Learn more at: brainly.com/question/11194034?referrer=searchResults
The primary condition for a reaction to reach dynamic equilibrium is that "rate of forward reaction must be equal to the rate of reverse reaction." Furthermore, in a state of dynamic equilibrium, it has a unique synthesis wherein reactants are converted to products and vice versa.
Answer:
The answer to your question is molality = 0.34
Explanation:
Data
mass of NaBr = 14.57 g
mass of water = 415 g.
molality = ?
Process
1.- Calculate the molar mass of NaBr
NaBr = 23 + 80 = 103 g
2.- Calculate the moles of NaBr
103 g of NaBr ------------------ 1 mol
14.57 g of NaBr --------------- x
x = (14.57 x 1) / 103
x = 14.57 / 103
x = 0.141 moles
3.- Calculate the molality
molality = moles / volume
-Substitution
molality = 0.141 / .415
-Result
molality = 0.34
1. Leave everything alone and don't touch the glass .
2. Tell a Teacher .
3. And that's it .