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Igoryamba
3 years ago
11

A basketball player made 83 out of 100 attempted free throws. What percent of free throws was​ made?

Mathematics
2 answers:
sesenic [268]3 years ago
7 0

Answer:

83%

Step-by-step explanation:

83/100=.83

Lera25 [3.4K]3 years ago
5 0

Answer:

83%

Step-by-step explanation:

83/100 = .83

0.83 x 100 to get in percent

83%

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What is ?/? + 2/7 =1
lapo4ka [179]

Answer:

5/7

Step-by-step explanation:

x +  \frac{2}{7}  = 1 \\  \\ x = 1 -  \frac{2}{7}  \\  \\ x =  \frac{7}{7}  -  \frac{2}{7}   \\  \\ x =  \frac{5}{7}

8 0
2 years ago
Read 2 more answers
Did i get number 2 right or wrong if i got it wrong tell me the answer
weeeeeb [17]

Answer:

Wouldn't it be 1/3 ??

because there is one column filled and there are three columns so that would make it 1/3 out of 3

4 0
3 years ago
Why can you use fraction multiplication to check the answer to a fraction division problem? How do you use multiplication to che
erica [24]
Fraction division is basically multiplication of a reciprocal.

For example (1/4)/(1/8) = (1/4)x(8/1)=2

Multiplication of the answer and the piece that divides (in this case 2 x 1/8), you should get the piece that is being divided (in this case 1/4). If that is correct, then your division is correct.
6 0
4 years ago
Read 2 more answers
Solve using Fourier series.
Olin [163]
With 2L=\pi, the Fourier series expansion of f(x) is

\displaystyle f(x)\sim\frac{a_0}2+\sum_{n\ge1}a_n\cos\dfrac{n\pi x}L+\sum_{n\ge1}b_n\sin\dfrac{n\pi x}L
\displaystyle f(x)\sim\frac{a_0}2+\sum_{n\ge1}a_n\cos2nx+\sum_{n\ge1}b_n\sin2nx

where the coefficients are obtained by computing

\displaystyle a_0=\frac1L\int_0^{2L}f(x)\,\mathrm dx
\displaystyle a_0=\frac2\pi\int_0^\pi f(x)\,\mathrm dx

\displaystyle a_n=\frac1L\int_0^{2L}f(x)\cos\dfrac{n\pi x}L\,\mathrm dx
\displaystyle a_n=\frac2\pi\int_0^\pi f(x)\cos2nx\,\mathrm dx

\displaystyle b_n=\frac1L\int_0^{2L}f(x)\sin\dfrac{n\pi x}L\,\mathrm dx
\displaystyle b_n=\frac2\pi\int_0^\pi f(x)\sin2nx\,\mathrm dx

You should end up with

a_0=0
a_n=0
(both due to the fact that f(x) is odd)
b_n=\dfrac1{3n}\left(2-\cos\dfrac{2n\pi}3-\cos\dfrac{4n\pi}3\right)

Now the problem is that this expansion does not match the given one. As a matter of fact, since f(x) is odd, there is no cosine series. So I'm starting to think this question is missing some initial details.

One possibility is that you're actually supposed to use the even extension of f(x), which is to say we're actually considering the function

\varphi(x)=\begin{cases}\frac\pi3&\text{for }|x|\le\frac\pi3\\0&\text{for }\frac\pi3

and enforcing a period of 2L=2\pi. Now, you should find that

\varphi(x)\sim\dfrac2{\sqrt3}\left(\cos x-\dfrac{\cos5x}5+\dfrac{\cos7x}7-\dfrac{\cos11x}{11}+\cdots\right)

The value of the sum can then be verified by choosing x=0, which gives

\varphi(0)=\dfrac\pi3=\dfrac2{\sqrt3}\left(1-\dfrac15+\dfrac17-\dfrac1{11}+\cdots\right)
\implies\dfrac\pi{2\sqrt3}=1-\dfrac15+\dfrac17-\dfrac1{11}+\cdots

as required.
5 0
3 years ago
What is the surface area of the following cylinder in square centimeters? 25 mm 1 cm 471 cm 2 2 31.4 cm 47.1 cm 2 54.95 cm 2​
Fittoniya [83]

Answer:

54.95 cm 2.

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
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