Answer: -1/2 or -0.5.
Explanation: -2- -1, -6- -2= -0.5
The z-score of the information given is:
z=(x-μ)/σ
where
μ-mean
σ- standard deviation
from the information given:
x=93.02
μ=89
σ=√625=25
hence
z=(93.02-89)/25
z=0.1608
thus
P(X≥x)=1-0.5636=0.4364=43.64%

<h3>area of shaded figure= </h3>
<h2>area of whole rectangle</h2>
= lengthx breadth=15x30= 450 cm²
<h3>area of unshaded region= lengthx breadth= (30-8)x 15cm²= 22x 15cm²= 330cm²</h3>
<h3>are of shaded region</h3>
= area of whole rectangle -area of unshaded region= 450cm²-330cm²= 120cm²
therefore 120 is correct answer
The second choice should be correct
This is a great question, but it's also a very broad one. Please find and post one or two actual rational expressions, so we can get started on specifics of how to find vertical and horiz. asymptotes.
In the case of vert. asy.: Set the denom. = to 0 and solve for x. Any real x values that result indicate the location(s) of vertical asymptotes.