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guapka [62]
3 years ago
9

Which is the simplified form of (9 c Superscript negative 9 Baseline) Superscript negative 3?

Mathematics
2 answers:
olga55 [171]3 years ago
7 0

Answer:

9c27

Step-by-step explanation:

SVETLANKA909090 [29]3 years ago
4 0

B) 1/729 c^27

I just took the quiz on edge

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Anthony works at a clothing store and gets a 15% employee discount.If he purchase p pants and s shirts his total can be found us
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Answer:

$192.95

Step-by-step explanation:

$35 x 4 pants = $140

$14.50 x 6 shirts = $87

140 + 87 = $227

227(15%) = $34.05

227 - 34.05 = $192.95

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Find the surface area of the prism.<br> T<br> 5 cm<br> 4 cm<br> 9 cm
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Help me please I'm bad at geometry​
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It’s actually all except bottom left
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Which graph COULD represent the table of values?<br> A)a<br> B)b<br> C)c<br> D)d
Basile [38]

Answer:

Option 2 or B

Step-by-step explanation:

B, if you look at the data table, you can notice that x and y are decreasing (therefore going down). I hope this helps?

4 0
3 years ago
the participants in a television quiz show are picked from a large pool of applicants with approximately equal numbers of men an
Nostrana [21]

Answer:

The probability of getting 2 or fewer women when 10 people are picked

P(x≤ 2) = \frac{56}{1024} = 0.0546

Step-by-step explanation:

The participants in a television quiz show are picked from a large pool of applicants with approximately equal numbers of men and women

That is probability of participants of television quiz of equal numbers of men and women that is 50 %of men and 50% of women.

p = 50/100 = 1/2

q = 1-p = 1 - 1/2 = 1/2

n =10

we will use binomial distribution p(x =r) = n_{cr} p^{r} q^{n-r}

The probability of getting 2 or fewer women when 10 people are picked

P(x≤ 2) = P(x=0)+P(x=1)+P(x=2)

          = 10_{c0} \frac{1}{2} ^{0} (\frac{1}{2}) ^{10-0}+ 10_{c1} \frac{1}{2} ^{1} (\frac{1}{2}) ^{10-1   \\   + 10_{c2} \frac{1}{2} ^{2} (\frac{1}{2}) ^{10-2

          by using formula n_{cr} =\frac{n!}{(n-r)!r!}

on simplification we get

     = 10_{c0}  (\frac{1}{2}) ^{10}+ 10_{c1} (\frac{1}{2}) ^{10) + 10_{c2} (\frac{1}{2}) ^{10)

    = 1  (\frac{1}{2}) ^{10}+ 10(\frac{1}{2}) ^{10)+45  (\frac{1}{2}) ^{10}

  = \frac{56}{1024} = 0.0546

<u>Conclusion</u>:-

The probability of getting 2 or fewer women when 10 people are picked

P(x≤ 2) = \frac{56}{1024} = 0.0546

8 0
3 years ago
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