Question

Approximately 10% of people are left-handed. If 15 people are selected at random, what is the probability exactly 2 are left-handed? Use the Binomialpdf(n, p, x) command on your calculator with the single option for the TI36X-Pro. Give your answer to 3 decimal places. If you do not have your calculator, you can use the command =BINOM.DIST(x,n,p,cumulative=0).

Answer 1

Answer:

Probability that exactly 2 left handed people will be selected from 15 people is 0.267

Step-by-step explanation:

We are given the following information:

We treat left-handed people as a success.

P(Left handed people) = 10% = 0.10

The number of people follows a binomial distribution, where

Formula:

$P(X=x) = \binom{n}{x}.p^x.(1-p)^{n-x}$

where n is the total number of observations, x is the number of success, p is the probability of success.

Now, we are given n = 15 and x = 2

We have to evaluate:

$P(x = 2) = \binom{15}{2}(0.10)^2(1-0.10)^{13}\\= 0.267$

Probability that exactly 2 left handed people will be selected from 15 people is 0.267