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muminat
3 years ago
13

The sum of the reciprocals of 2 consecutive integers is 32/132

Mathematics
1 answer:
lisabon 2012 [21]3 years ago
4 0
SOLUTION:

x + x + 1 = 132 / 32

2x + 1 = 33 / 8

2x = 33 / 8 - 1

2x = 25 / 8

x = 25 / 8 / 2

x = 25 / 16

The first number is 25 / 16. Therefore, as the second number is consecutive we simply add 1 to the first number to achieve the second number as displayed below:

Second number:

= x + 1

= 25 / 16 + 1

= 36 / 16

= 9 / 4

ANSWER:

Therefore, the first number is 25 / 16 and the second number is 9 / 4.

Hope this helps! :)
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At a time denoted as t = 0 a technological innovation is introduced into a community that has a fixed population of n people.
PSYCHO15rus [73]

Answer:

The differential equation is

dR/dt = -k(2x - n)dx/dt for k > 0

Assuming initially, one person adopts the innovation, then

dR/dt = 0

Step-by-step explanation:

Total number of people in the community is "n"

At time t, the number of people who

have adopted the innovation is "x(t)"

This Tells us that (n - x) people haven't adopted the innovation.

It is assumed that the rate at which the innovations spread through the community is jointly proportional to the number of people who have adopted it and the number of people who have not adopted it.

So

Let R be the rate, then

R is proportional to x(n - x)

R = kx(n - x) = -kx(x - n)

Differentiating this with respect to time, t, we have

dR/dt = (-k(x - n) - kx)dx/dt

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And this is the differential equation.

Assuming initially, one person adopts the innovation, then

dR/dt = 0

3 0
4 years ago
In triangle ABC, angle A is 59 degrees & the side length adjacent to angle A is 19. Find the side length opposite angle A
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Answer:

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4 0
3 years ago
1. Let the test statistics Z have a standard normal distribution when H0 is true. Find the p-value for each of the following sit
Nonamiya [84]

Answer:

1 a  p -value  =   0.030054

1b   p -value  =   0.0029798

1c  p -value  = 0.0039768  

2a  p-value  =   0.00099966

2b  p-value  =  0.00999706

2c  p-value   = 0.0654412

Step-by-step explanation:

Considering question a

  The alternative hypothesis is H1:μ>μ0

   The test statistics is  z =1.88

Generally from the z-table  the  probability of   z =1.88 for a right tailed test is

    p -value  =  P(Z > 1.88) = 0.030054

Considering question b

  The alternative hypothesis is H1:μ<μ0

   The test statistics is  z=−2.75

Generally from the z-table  the  probability of   z=−2.75 for a left tailed test is

    p -value  =  P(Z < -2.75) = 0.0029798

Considering question c

  The alternative hypothesis is H1:μ≠μ0

   The test statistics is  z=2.88

Generally from the z-table  the  probability of  z=2.88 for a right  tailed test is

    p -value  = P(Z >2.88) =  0.0019884    

Generally the p-value for the two-tailed test is

    p -value  = 2 *  P(Z >2.88) =  2 * 0.0019884    

=> p -value  = 0.0039768  

Considering question 2a

    The alternative hypothesis is H1:μ>μ0

     The sample size is  n=16

     The  test statistic is  t =  3.733

Generally the degree of freedom is mathematically represented as

        df =  n - 1

=>     df =  16 - 1

=>     df =  15

Generally from the t distribution table  the probability of   t =  3.733 at a degree of freedom of  df =  15 for a right tailed test is  

       p-value  =  t_{3.733 ,  15} = 0.00099966

Considering question 2b

    The alternative hypothesis is H1:μ<μ0

     The degree of freedom is df=23

     The  test statistic is ,t= −2.500

Generally from the t distribution table  the probability of   t= −2.500 at a degree of freedom of  df=23 for a left  tailed test is  

       p-value  =  t_{-2.500 ,  23} = 0.00999706

Considering question 2c

    The alternative hypothesis is H1:μ≠μ0

     The sample size is  n= 7

     The  test statistic is ,t= −2.2500

Generally the degree of freedom is mathematically represented as

        df =  n - 1

=>     df =  7 - 1

=>     df =  6

Generally from the t distribution table  the probability of   t= −2.2500 at a degree of freedom of  df =  6 for a left   tailed test is  

       t_{-2.2500 , 6} = 0.03272060

Generally the p-value  for t= −2.2500 for a two tailed test is

     p-value  =  2 *  0.03272060 = 0.0654412

4 0
3 years ago
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