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Sati [7]
3 years ago
15

Devisibility rules for 3, 6, and 9

Mathematics
1 answer:
fenix001 [56]3 years ago
3 0

Answer:

<u>★</u><u> </u><u>Divisibility</u><u> </u><u>rule</u><u> </u><u>for</u><u> </u><u>3</u><u> </u><u>-</u>

If the sum of all the digits divisible by 3 then the number is divisible by 3.

Here, we take an example for better understanding -

<u>Example</u><u> </u><u>1</u><u> </u><u>-</u> 3525

Add up the digits - 3 + 5 + 2 + 5

→ 15

As, 15 is divisible by 3. So, 3525 is a factor of 3.

★<u> </u><u>Divisibility</u><u> rule</u><u> </u><u>for</u><u> </u><u>6</u><u> </u><u>-</u>

A number is to be divisible by 6 , if the number is also divisible by 2 and 3.

<u>Exampl</u><u>e</u><u> </u><u>2</u><u> </u><u>-</u> 132

Add up the digits = 1 + 3 + 2 = 6

As, 6 is divisible by 2 and it's also divisible by 3. Then, 132 is a factor of 6.

★ <u>Divisibility</u><u> rule</u><u> for</u><u> </u><u>9</u><u> </u><u>-</u>

If the sum of all the digits is divisible by 9 then the number is divisible by 9. Just like we'd in 3.

<u>Example</u><u> </u><u>3</u><u> </u><u>-</u> 1052

Add up the digits - 10 + 5 + 2 = 17

As, 17 is not divisible by 9. So, 1052 is also not divisible by 9.

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