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How to find rapidly the coordinates of Q:
since Q is the center of gravity of the triangle ABC, so we have the following vector relationship
vecQA +vecQB +vecQC =<span>vec0
</span><span>vecQA=(x-3, y+2)
</span><span>vecQB=(x-1, y+5)
</span><span>vecQC=(x-7, y+5)
</span><span>vec0=(0, 0)
</span>
so, vecQA +vecQB +vecQC =<span>vec0 is equivalent to
</span>x-3 +x-1+x-7 =0, and y+2+y+5+<span>y+5=0 so 3x-11=0 implies x=11/3
</span><span>and 3y+12=0 implies y=-12/3
finally the </span><span>the coordinates of point Q is (11/3, -4)</span><span>
</span>
Answer:
$864.82
Step-by-step explanation:
Just add them together.
Answer:
because x^n+1 =
the number which is n and n is an odd number and my odd number is 3 so
x^3+1= 4
= x^4
Answer:
There are 232 students at the school.
Step-by-step explanation:
Let s represent the number of students at the school. We are told ...
174 = 75% × s
174/0.75 = s = 232 . . . . . divide by the coefficient of s
There are 232 students at the school.
