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puteri [66]
4 years ago
14

A cup of coffee (140g) cools from 75°C down to comfortable room temperature 20°C. How much energy does it release to the surroun

dings
Chemistry
1 answer:
Thepotemich [5.8K]4 years ago
4 0

Given that the mass of coffee in the cup = 140 g

Final temperature = 20^{0}C

Initial temperature = 75^{0}C

Let us assume the specific heat of coffee is equal to that of water = 4.184\frac{J}{g^{0}C }

Temperature change = T(final) - T(initial) = (20 - 75 )^{0}C

                                                                   =- 55 ^{0}C

-Heat given out by coffee = heat absorbed by the surroundings

Heat released into the surroundings =-(mC(T_{final}-T_{initial}))

                                             = -(140g)4.184\frac{J}{g^{0}C }( -55^{0}C)

                                             = 32,217 J

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Rina8888 [55]

Answer:

HCL and CaCl2

Explanation:

Since calcium hydroxide is a base, then it needs an acid to neutralise it.

HCL is an acid, it can neutralize calcium hydroxide through reacting the two together.

The resultant salt shall be calcium chloride ( CaCl2 )

Reaction of calcium hydroxide and HCl results into Ca(OH)Cl, CaCl2,

Where Ca(OH)Cl is an aqueous solution and calcium chloride is a base.

Hope the answer helps out.

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3 years ago
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Answer:

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Explanation:

Step 1: Given data

Width of the tank (w): 18 in

Height of the tank (h): 11 in

Depth of the tank (d): 5 in

Step 2: Calculate the volume of the tank in in³

The fuel tank is a cuboid. We can calculate its volume using the following expression.

V = w × h × d

V = 18 in × 11 in × 5 in

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We will use the relationship 1 m³ = 61023.7 in³.

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shepuryov [24]

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Explanation:

Avogadro's hypothesis gives us an excellent understanding that 1mole of any substance contains 6.02x10^23 molecules. This means that 1mole H2O also contains 6.02x10^23 molecules.

Now, if 1 mole of H2O contains 6.02x10^23 molecules

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