Question

How many molecules are contained in 127 grams of iodine?

Answer 1

3.4 molecules is in 127 grams of iodine

Answer 2

Answer : The number of molecules contained in 127 grams of iodine are, $5.96\times 10^{23}$

Solution : Given,

Mass of iodine = 127 g

Molar mass of iodine = 126.9 g/mole

First we have to calculate the moles of iodine.

$\text{Moles of iodine}=\frac{\text{Mass of iodine}}{\text{Molar mass of iodine}}=\frac{127g}{127.9g/mole}=0.99mole$

Now we have to calculate the number of molecules of iodine.

As, 1 mole of iodine contains $6.022\times 10^{23}$ number of molecules of iodine

So, 0.99 mole of iodine contains $0.99\times (6.022\times 10^{23})=5.96\times 10^{23}$ number of molecules of iodine

Therefore, the number of molecules contained in 127 grams of iodine are, $5.96\times 10^{23}$