Answer:
8.32 s⁻¹
Explanation:
Given that:
The concentration of myosin = 25 pmol/L
R_max = 208 pmol/L/s
The objective is to determine the turnover number of the enzyme molecule myosin, which has a single active site.
In a single active site of enzyme is known to be a region where there is binding of between substrate molecules, thereafter undergoing chemical reaction.
The turnover number of the enzyme is said to be the number of these substrate molecule which binds together are being converted into products.
The turnover number of the enzyme molecule of myosin can be calculated by the expression: 
⇒ 
= 8.32 s⁻¹
There isn't anything there resubmit it
Answer:
Ksp = 3.24 x 10⁻⁴
Explanation:
The dissociation equilibrium for a generic salt AB is:
AB(s) ⇄ A⁺(aq) + B⁻(aq)
s s
For instance, the expression for the Ksp constant is:
Ksp = [A⁺] [B⁻] = s x s = s²
According to the problem, 0.0180 mol of the salt is soluble in 1.00 L os water. That means that the solubility of the salt (s) is equal to 0.0180 mol per liter.
s = moles of solute/L of solution = 0.0180 mol/L
Thus, we calculate Ksp from the s value as follows:
Ksp = s² = (0.0180)² = 3.24 x 10⁻⁴
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