1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
neonofarm [45]
3 years ago
9

According to the kinetic-molecular theory, which sequence represents the relationship between pressure and volume of an ideal ga

s?
A. more gas particles -> more collisions -> higher pressure
B. smaller volume -> crowded particles -> more collisions -> higher pressure
C. more gas particles -> more kinetic energy -> more volume -> higher pressure
D. smaller volume -> crowded particles -> less collisions -> lower pressure
Chemistry
1 answer:
Nata [24]3 years ago
7 0

Answer:

A I think

Explanation:

You might be interested in
Calculate the number of mol of solute in 8.00 × 102 mL of 0.250 M HCl.
Alenkasestr [34]

Moles = Volume*Molarity

           = 0.008*0.250

           = 0.002 mol

8 0
3 years ago
Given that the concentration of myosin is 25pmol·L−1 and Rmax(Vmax)=208pmol·L−1·s−1 , determine the turnover number of the enzym
DedPeter [7]

Answer:

8.32 s⁻¹

Explanation:

Given that:

The concentration of myosin = 25 pmol/L

R_max = 208 pmol/L/s

The objective is to determine the  turnover number of the enzyme molecule myosin, which has a single active site.

In a single active site of enzyme is known to be a region where there is binding of between substrate molecules, thereafter undergoing chemical reaction.

The turnover number of the enzyme is said to be the number of these substrate molecule which binds together are being converted into products.

The turnover number of the enzyme molecule of myosin can be calculated by the expression: \dfrac{R_{max}}{concentration}

⇒ \dfrac{208 pmol/L/s}{25 pmol/L}

= 8.32 s⁻¹

4 0
4 years ago
Which of the following is true about an actual yield?
My name is Ann [436]

There isn't anything there resubmit it

6 0
3 years ago
At 25 ∘C only 0.0180 mol of the generic salt AB is soluble (at equilibrium) in 1.00 L of water.What is the value for Ksp for thi
Ghella [55]

Answer:

Ksp = 3.24 x 10⁻⁴

Explanation:

The dissociation equilibrium for a generic salt AB is:

AB(s) ⇄ A⁺(aq) + B⁻(aq)

              s            s

For instance, the expression for the Ksp constant is:

Ksp = [A⁺] [B⁻] = s x s = s²

According to the problem, 0.0180 mol of the salt is soluble in 1.00 L os water. That means that the solubility of the salt (s) is equal to 0.0180 mol per liter.

s = moles of solute/L of solution = 0.0180 mol/L

Thus, we calculate Ksp from the s value as follows:

Ksp = s² = (0.0180)² = 3.24 x 10⁻⁴

6 0
3 years ago
In addition to the six elements most prevalent in living things there are other elements that are required for human life. Which
d1i1m1o1n [39]
B. Calcium! I hope this help.
If your bones don't have enough calcium you get osteoporosis. 
5 0
4 years ago
Read 2 more answers
Other questions:
  • How many moles are equal to 89.23 g of calcium oxide?
    15·2 answers
  • What is the order of classification of matter?
    15·1 answer
  • In the reaction between bromine and sodium a bromine atom gains an electron.what ion is formed.is the bromine oxidized,or is it
    8·1 answer
  • Match each substance with its correct definition.
    14·2 answers
  • “Enter the conjugate acids of no2- and no3-“
    14·1 answer
  • Los átomos que no poseen _______________ son conocidos como _________________ ________________. Los átomos que poseen carga se d
    7·1 answer
  • In the electron configuration 2-8-3-1, which shell contains electrons with the greatest energy?
    14·1 answer
  • What are two types of energy?
    10·1 answer
  • Does an electron cause an electromagnetic wave to vibrate
    15·1 answer
  • Please Help! Is it possible to have two other resonance structures with the double bond being connected to the chlorine.
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!