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3 years ago

6

The annual rainfall (in inches) in Western Colorado is modeled by a distribution with the following cumulative distribution func

tion. Determine the mean and the variance of the annual rainfall in this region

1 answer:

kirill115 [55]3 years ago

8 0

Stanky chesse Sandwich Ummmm

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Debbie works in a warehouse. Each cart that she uses to move boxes can hold no more than 200 pounds. If each box she puts on the

Nady [450]

Answer:

She can put a maximum of 10 boxes in the cart.

Step-by-step explanation:

Given that each cart that Debbie uses to move the boxes supports a maximum of 200 pounds, and that each box that she places in the cart weighs 20 pounds, to determine the maximum number of boxes that can fit in the cart, the following calculation must be performed :

200/20 = X

20/2 = X

10 = X

Thus, she can put a maximum of 10 boxes in the cart.

5 0

2 years ago

F(x) = -x^3+ 6x – 7 at x = 2

vodomira [7]

Answer:

f(2)= -4

Step-by-step explanation:

f(x)= -x^3 + 6x - 7

f(2) = -2^3 + 6*2 - 7

f(2)= -8 +12 -7

f(2)= 3-7

f(2)= -4

4 0

2 years ago

Given f(x) = x^2-3 and g(x)=x+2/x. Find (g°f)(4)

goblinko [34]

Answer:

15/13

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Two angles are complementary and the measure of one is 36

marysya [2.9K]

Answer:The angles are 63 degrees and 27 degrees
This is true because when you subtract 27 from 63 you get 36. And when you add 27 to 63 you get 90 aka the complimentary angle we’re looking for.

7 0

2 years ago

Given the following diagram, find the missing measure.<br>*

BigorU [14]

Option C:

x = 30

Solution:

The given image is a triangle.

angle 1, angle 2 and angle 3 are interior angles of a triangle.

angle 4 is the exterior angle of a triangle.

m∠4 = 2x°, $m\angle2=\frac{4}{3}x^\circ$ , m∠3 = 20°

Exterior angle theorem:

<em>In triangle, the measure of exterior angle is equal to the sum of the opposite interior angles.</em>

By this theorem,

m∠4 = m∠2 + m∠3

$$2x^\circ=\frac{4}{3}x^\circ+20^\circ$

Subtract $\frac{4}{3}x^\circ$ on both sides of the equation.

$$2x^\circ-\frac{4}{3}x^\circ=20^\circ$

To make the denominator same and then subtract.

$$\frac{6}{3}x^\circ -\frac{4}{3}x^\circ=20^\circ$

$$\frac{2}{3}x^\circ =20^\circ$

Multiply by $\frac{3}{2}$ on both sides of the equation.

x° = 30°

x = 30

Hence option C is the correct answer.

6 0

3 years ago