Answer:
Final mass of Iron bar will be 621.105 g.
Mass of rust = 126.730 g
Explanation:
Exactly one- eighth of the Iron turns to rust. That means, the mass of Iron that under go the process of rusting() = 565 × = 70.625 g
So, the mass of pure Iron after rusting will be = 565 - 70.625 = 494.375 g
Now the reaction of rusting as follows,
2Fe + →
Now, molecular weight of Iron = 55.84 g
So, moles of Iron undergoes the reaction is = = 1.26 mol
Molecular weight of = 159.68 g
Here 2 moles of Iron undergoes the reaction to produce 2 moles of Iron oxide.
Hence, 1.26 mol of Iron will produce 1.26 mole of Iron oxide.
Mass of = = 126.730 g
∴Mass of rust = 126.730 g
∴ Final mass of Iron bar = ( 494.375 + 126.730) = 621.105 g