Hey there !
Molecular Weight: 262.86 g/mol
Volume in liters : 1,000 mL => 1,000 / 1000 => 1 L
Number of moles of solution :
number of moles = volume x molarity
number of moles = 1 x 0.3 => 0.3 moles
Therefore:
1 mole Mg₃(PO₄)₂ ------------------- 262.86 g
0.3 moles ----------------------------- mass of Mg₃(PO₄)₂ ??
mass of Mg₃(PO₄)₂ = 0.3 x 262.86 / 1
mass of Mg(PO₄)₂ => 78.858 g
Hope this helps!
Answer:Iron is extracted from iron ore in a huge container called a blast furnace. Iron ores such as haematite contain iron(III) oxide, Fe 2O 3. The oxygen must be removed from the iron(III) oxide in order to leave the iron behind. Reactions in which oxygen is removed are called reduction reactions.
The mass percent of each compound is
- (NaBr*2H2O)=85.71 percent
- (MgBr2*6H2O)=14.29 percent
<h3>The mass percent equation is as follows.</h3>
The formula mass percent is the most effective way to express mass percent: mass percent = (mass of chemical x total mass of compound) times 100. Add 100 to the top value to get the value expressed as a percentage.
<h3>What percentage by mass does a solution have?</h3>
By multiply the grams of solute per gram of solution by 100, it is possible to get the mass percent of a solution.
The molar mass of each element and the mass of each element contained in a mole of the compound are both solved for in the Mass Percent formula.
Learn more about Mass Percent here
brainly.com/question/26150306
#SPJ4
Answer:
P₂ = 0.8 atm
Explanation:
Given data:
Initial pressure = 1 atm
Initial volume = 7 L
Final volume = 9 L
Final pressure = ?
Solution:
P₁V₁ = P₂V₂
P₁ = Initial pressure
V₁ = Initial volume
P₂ = Final pressure
V₂ = Final volume
Now we will put the vales in formula.
P₁V₁ = P₂V₂
P₂ = P₁V₁ /V₂
P₂ = 1 atm × 7 L / 9 L
P₂ = 7 atm. L / 9 L
P₂ = 0.8 atm
Answer:
For the tetrahedral case the repulsion is smaller.
Explanation:
It is smaller for the tetrahedral case because he angles for tetrahedral molecules are greater (109.5) then for octahedral molecules (90). The greater the distance between the atoms the smaller the repulsion, and so the bigger are angles the bigger is distance.