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Musya8 [376]
4 years ago
14

Logs in a fire, and charged batteries are examples of?

Chemistry
1 answer:
vlabodo [156]4 years ago
7 0

Answer:

Logs in a fire is an example of something burning, also changing its state of form. I think thats chemical change; going from wood to ashes. And charged batteries means they haven't been used yet or they were just charged, resulting in physical change.

Explanation:

I just learned this in science.

I hope this helps!

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2. What type of bonding would be expected between the following atoms?
maksim [4K]
A.) covalent
c.) covalent
b.) ionic
d.) covalent
7 0
3 years ago
PLEASE HELP ME 20 POINTS!!!!!!!!!!
zhuklara [117]

2.66 molecules of ammonia are produced

Explanation:

We have bellow the chemical reaction between nitrogen (N₂) and hydrogen (H₂) which produce ammonia (NH₃):

N₂ + 3 H₂ → 2 NH₃

From the chemical reaction we see that 1 molecule of nitrogen reacts with 3 molecules of hydrogen, so 4 molecules of nitrogen will react with 12 molecules of hydrogen but we only have 4 molecules of hydrogen available, so the limiting reactant will the hydrogen. Knowing this we devise the following reasoning:

if       3 molecules of hydrogen produces 2 molecules of ammonia

then 4 molecules of hydrogen produces X molecules of ammonia

X = (4 × 2) / 3 = 2.66 molecules of ammonia

However it does not make sense to produce half a molecule of something (you can not do this in the real world), the problem will make sense if you talk about the number of moles of each substance, because in 1 mole of substance you have 6.022 × 10²³ molecules.

You may find in the attached picture the drawing of the molecules.

Learn more about:

limiting reactant

brainly.com/question/13979150

#learnwithBrainly

3 0
3 years ago
The boiling point of a solution will ____________ and the freezing point will ____________ with _____________ concentration of a
earnstyle [38]
Answer is option (C)

Reason: change in boiling/melting point is proportional to molality of solvent.
4 0
3 years ago
Read 2 more answers
The enthalpy of vaporization of liquid water at 100°C is 2257 kJ/kg. Determine the enthalpy for apordato of iuod eeat capacity o
igomit [66]

Explanation:

The given data is as follows.

         T_{1} = 100^{o}C,       T_{2} = 10^{o}C

       \Delta H_{vap1} = 2257 kJ/kg,     \Delta H_{vap2} = ?

For water, C_{p} = 4.184 kJ/kg ^{o}C

Formula to calculate heat of vaporization is as follows.

  \Delta H_{vap1} - \Delta H_{vap2} = C_{p}(T_{1} - T_{2})

Hence, putting the values into the above formula as follows.

\Delta H_{vap1} - \Delta H_{vap2} = C_{p}(T_{1} - T_{2})

2257 kJ/kg - \Delta H_{vap2} = 4.184 kJ/kg ^{o}C (100 - 10)^{o}C

            \Delta H_{vap2} = 2257 kJ/kg - 376.56 kJ/kg

                                       = 1880.44 kJ/kg

Thus, we can conclude that enthalpy of liquid water at 10^{o}C is 1880.44 kJ/kg.

3 0
3 years ago
Which solution has the lower freezing point 1.0 M KBr or 1.0 M CaBr2?
N76 [4]
Answer: the solution 1.0 M Ca Br2.

This is becasue the freezing point depression is a colligative property.

A collegative property is one that depends on the number of particles in solution.

Each mole of KBr will produce two moles, one mole of potassium ion and one of bromine ion

 Each mole of CaBr2 will produce three moles, one of calcion ion and two of bromine ion.

Then, the depression of the frezzing point will be greater in the case of the CaBr2, leading to a lower freesing point of the 1.0 M soluction.
5 0
3 years ago
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