Answer:
2L
Explanation:
We'll begin by writing the balanced equation for the reaction this is illustrated below:
2H2 + O2 —> 2H2O
1 mole of a gas occupy 22.4L.
1 mole of O2 occupy 22.4L.
2 moles of H2O occupy = 2 x 22.4 = 44.8L.
From the balanced equation above,
22.4L of O2 produced 44.8L of H2O.
Therefore, 1L of O2 will produce = 44.8/22.4 = 2L.
Therefore, 1L of O2 will produce 2L of H2O.
The magnetic property of nails could be used to just pull them out with a magnet.
The difference in boiling points between water and iron or steel is hundreds of degrees Celsius so you could apply heat and just boil the water away.
At equilibrium the concentrations of:
[HSO₄⁻] = 0.10 M;
[SO₄²⁻] = 0.037 M;
[H⁺] = 0.037 M;
There is initially very little H+ and no SO₄²⁻ in the solution. A salt is KHSO₄⁻. All KHSO₄⁻ will split apart into K⁺ and HSO₄⁻ ions. [HSO₄⁻] will initially be present at a concentration of 0.14 M.
HSO₄⁻ will not gain H⁺ to produce H₂SO₄ since H₂SO₄ is a strong acid. HSO₄⁻ may act as an acid and lose H⁺ to form SO₄²⁻. Let the final H⁺ concentration be x M. Construct a RICE table for the dissociation of HSO₄²⁻.
R
⇄ 
I 
C

E

×
for
. As a result,
![\frac{[H^+]. [SO_4^2^-]}{HSO_4^-} = K_a](https://tex.z-dn.net/?f=%5Cfrac%7B%5BH%5E%2B%5D.%20%5BSO_4%5E2%5E-%5D%7D%7BHSO_4%5E-%7D%20%3D%20K_a)
is large. It is no longer valid to approximate that
at equilibrium is the same as its initial value.

×
× 
Solving the quadratic equation for
since
represents a concentration;

Then, round the results to 2 significant figure;
Learn more about concentration here:
brainly.com/question/14469428
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