A.) covalent
c.) covalent
b.) ionic
d.) covalent
2.66 molecules of ammonia are produced
Explanation:
We have bellow the chemical reaction between nitrogen (N₂) and hydrogen (H₂) which produce ammonia (NH₃):
N₂ + 3 H₂ → 2 NH₃
From the chemical reaction we see that 1 molecule of nitrogen reacts with 3 molecules of hydrogen, so 4 molecules of nitrogen will react with 12 molecules of hydrogen but we only have 4 molecules of hydrogen available, so the limiting reactant will the hydrogen. Knowing this we devise the following reasoning:
if 3 molecules of hydrogen produces 2 molecules of ammonia
then 4 molecules of hydrogen produces X molecules of ammonia
X = (4 × 2) / 3 = 2.66 molecules of ammonia
However it does not make sense to produce half a molecule of something (you can not do this in the real world), the problem will make sense if you talk about the number of moles of each substance, because in 1 mole of substance you have 6.022 × 10²³ molecules.
You may find in the attached picture the drawing of the molecules.
Learn more about:
limiting reactant
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Answer is option (C)
Reason: change in boiling/melting point is proportional to molality of solvent.
Explanation:
The given data is as follows.
,
= 2257 kJ/kg,
= ?
For water,
= 4.184 
Formula to calculate heat of vaporization is as follows.
= 
Hence, putting the values into the above formula as follows.
= 
= 
= 2257 kJ/kg - 376.56 kJ/kg
= 1880.44 kJ/kg
Thus, we can conclude that enthalpy of liquid water at
is 1880.44 kJ/kg.
Answer: the solution 1.0 M Ca Br2.
This is becasue the freezing point depression is a colligative property.
A collegative property is one that depends on the number of particles in solution.
Each mole of KBr will produce two moles, one mole of potassium ion and one of bromine ion
Each mole of CaBr2 will produce three moles, one of calcion ion and two of bromine ion.
Then, the depression of the frezzing point will be greater in the case of the CaBr2, leading to a lower freesing point of the 1.0 M soluction.