Ask question

Ask question

All categories

Marizza181 [45]

3 years ago

8

(WILL GIVE BRAINLESS)Throwing a paper airplane through the air is an example of A. fluid friction B. sliding friction C. rolling

friction D. solid friction

2 answers:

Scilla [17]3 years ago

8 0

Answer:

sliding friction

Explanation:

Ymorist [56]3 years ago

7 0

Answer:

D. solid friction

Explanation:

Its not a fluid, Its not sliding, and its not rolling, so therefor is solid friction

You might be interested in

The table shows the charge on three unknown subatomic particles.

brilliants [131]

Answer:

B. only particle Z

Explanation:

In the case of subatomic particles, those positive and neutral are located in the nucleus, and those with a negative charge on the outside.

8 0

4 years ago

Read 2 more answers

2C2H2(g)+5O2(g)=4CO2(g)+2H2O(g)

balandron [24]

The volume of ethyne, C₂H₂ required to produce 12 moles of CO₂ assuming the reaction is at STP is 134.4 L

<h3>Balanced equation</h3>

2C₂H₂(g) + 5O₂(g) --> 4CO₂(g) + 2H₂O(g)

From the balanced equation above,

4 moles of CO₂ were produced by 2 moles of C₂H₂

<h3>How to determine the mole of C₂H₂ needed to produce 12 moles of CO₂</h3>

From the balanced equation above,

4 moles of CO₂ were produced by 2 moles of C₂H₂

Therefore,

12 moles of CO₂ will be produce by = (12 × 2) / 4 = 6 moles of C₂H₂

<h3>How to determine the volume (in L) of C₂H₂ needed at STP</h3>

At standard temperature and pressure (STP),

1 mole of C₂H₂ = 22.4 L

Therefore,

6 moles of C₂H₂ = 6 × 22.4

6 moles of C₂H₂ = 134.4 L

Thus, we can conclude that the volume of C₂H₂ needed for the reaction at STP is 134.4 L

Learn more about stoichiometry:

brainly.com/question/14735801

#SPJ1

3 0

2 years ago

What is a vocab word for Friction?

Leona [35]

Answer: Friction is the resistance to motion of one object moving relative to another. It is not a fundamental force, like gravity or electromagnetism. Instead, scientists believe it is the result of the electromagnetic attraction between charged particles in two touching surfaces.

Explanation:

7 0

3 years ago

Calculate the amount (in grams) of kcl present in 75.0 ml of 2.10 m kcl

Lera25 [3.4K]

V = 75 mL = 0,075 L = 0,075 dm³
C = 2.1M
n = ?
---------------
C = n/V
n = C×V
n = 2.1×0,075
n = 0,1575 mol
--------
mKCl: 39+35.5 = 74,5 g/mol

74,5g --------- 1 mol
Xg ------------- 0,1575 mol
X = 74,5×0,1575
X = 11,73375g KCl

:•)

5 0

3 years ago

a student reacted 40 drops of an unknown amine with 20 drops of iodomethane in 2 ml of a suitable solvent mixture. after 15 minu

lutik1710 [3]

The compound formed is the quaternary ammonium salt N,N,N-trimethyl-1-phenylmethanaminium iodide.

Quaternary ammonium salts are formed when methyl iodide reacts with an amine. The quaternary ammonium salt is an ionic substance which often has a high melting point. Remember that the melting point of a substance can be used to identify the substance.

In this case, a student reacted 40 drops of an unknown amine with 20 drops of iodomethane in 2 ml of a suitable solvent mixture. after 15 minutes of reaction, a white precipitate formed. the precipitate was isolated and its melting point was recorded to be 178 °c. This precipitate must be N,N,N-trimethyl-1-phenylmethanaminium iodide (Benzyltrimethylammonium iodide) because it is a quaternary ammonium salt whose melting point is 178 °c.

Learn more: brainly.com/question/5325004

8 0

2 years ago