Answer:
Momentum,
Explanation:
The wave function of a particle is given by :
...............(1)
Where
x is the distance travelled
t is the time taken
k is the propagation constant
is the angular frequency
The relation between the momentum and wavelength is given by :
............(2)
From equation (1),
Use above equation in equation (2) as :
Since,
So, the x-component of the momentum of the particle is . Hence, this is the required solution.
'A' is correct. B, C, and D are false statements.
Answer:
Ax = 0
Ay = 6 m
Bx = 8 cos phi = cos 34 = 6.63 m
By = 8 sin phi = 8 sin (-34) = -4.47 m
Rx = Ax + Bx = 0 + 6.63 = 6.63 m
Ry = Ay + By = 6 - 4.47 = 1.53 m
R = (6.63^2 + 1.53^2)^1/2 = 6.80 m
tan theta = Ry / Rx = 1.53 / 6.8 = ,225
theta = 12.7 deg
The characteristics of the velocity vector used to find the results for the direction of acceleration and velocity are:
- Acceleration is towards the center of the circle
- The velocity is tangent to the circle counterclockwise.
Newton's Second Law establishes a relationship between force, mass and acceleration of bodies.
<h3>Centripetal acceleration.
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In the case of circular motion there is a constant change in the direction of the velocity vector, even when its module remains constant, this change in direction points towards the center of the circle, so that the module is constant.
They indicate that the satellite is moving counterclockwise, therefore the speed must go to the left (counterclockwise) tangential to the circle.
In conclusion using the characteristics of the velocity vector we can find the results for the direction of acceleration and velocity are:
- Acceleration is towards the center of the circle
- The velocity is tangent to the circle counterclockwise.
Learn more about centripetal acceleration here: brainly.com/question/25243603
Given Information:
Angular displacement = θ = 51 cm = 0.51 m
Radius = 1.8 cm = 0.018 m
Initial angular velocity = ω₁ = 0 m/s
Angular acceleration = α = 10 rad/s
²
Required Information:
Final angular velocity = ω₂ = ?
Answer:
Final angular velocity = ω₂ = 21.6 rad/s
Explanation:
We know from the equations of kinematics,
ω₂² = ω₁² + 2αθ
Where ω₁ is the initial angular velocity that is zero since the toy was initially at rest, α is angular acceleration and θ is angular displacement.
ω₂² = (0)² + 2αθ
ω₂² = 2αθ
ω₂ = √(2αθ)
We know that the relation between angular displacement and arc length is given by
s = rθ
θ = s/r
θ = 0.51/0.018
θ = 23.33 radians
finally, final angular velocity is
ω₂ = √(2αθ)
ω₂ = √(2*10*23.33)
ω₂ = 21.6 rad/s
Therefore, the top will be rotating at 21.6 rad/s when the string is completely unwound.