<span>Here I think you have to find the velocity in x and y components where x is east and y is north
So as air speed indicator shows the negative speed in y component and adding it in
air speed while multiplying with the direction component we will get the velocity as velocity is a vector quantity so direction is also required
v=-28 m/s y + 18 m/s (- x/sqrt(2) - y/sqrt(2))
solving
v= -12.7 m/s x-40.7 m/s y
if magnitude of velocity or speed is required then
speed= sqrt(12.7^2 + 40.7^2)
speed= 42.63 m/s
if angle is asked
angle = arctan (40.7/12.7)
angle = 72.67 degrees south of west</span>
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Answer:
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all I got
Answer:
The time taken to travel is, t = 12 minutes
Explanation:
Given data,
The speed of the car, v = 60 km/h
The distance of travel, d = 12 km
The time taken for the travel is t = ?
The speed is defined as the distance divided by the time taken to travel. The formula for speed is,
v = d/t
∴ t = d/v
t = 12 km / 60 km/h
t = 0.2 h
t = 12 minutes
Hence, the time taken to travel is, t = 12 minutes.
v = 
and
a = 
We have acceleration and velocity so:
3 =
88.3 =
In the acceleration equation we can isolate for v and then plug it back into the other equation to solve...
So...
Divide by three and
t = 29.4 s
