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nika2105 [10]
3 years ago
6

Will give correct answer brainliest

Physics
2 answers:
uranmaximum [27]3 years ago
4 0

Answer:

the height would be 3.5metres

levacccp [35]3 years ago
3 0
The potential energy= mass times gravity times height. However, we are missing height. Gravity is a constant that is 9.8 on Earth. We then solve for height by dividing 350 by 10 and then 9.8 to get about 3.5.
TLDR: 3.5
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shows a conical pendulum, in which the bob (the small object at the lower end of the cord) moves in a horizontal circle at const
Contact [7]

Answer:

a) T=0.40 N

b) T=1.9 s

Explanation:

Let's find the radius of the circumference first. We know that bob follows a circular path of circumference 0.94 m, it means that the perimeter is 0.94 m.

The perimeter of a circunference is:

P=2\pi r=0.94

r=\frac{0.94}{2\pi}=0.15 m

Now, we need to find the angle of the pendulum from vertical.

tan(\alpha)=\frac{r}{L}=\frac{0.15}{0.90}=0.17

\alpha=9.44 ^{\circ}

Let's apply Newton's second law to find the tension.

\sum F=ma_{c}=m\omega^{2}r

We use centripetal acceleration here, because we have a circular motion.

The vertical equation of motion will be:

Tcos(\alpha)=mg (1)

The horizontal equation of motion will be:

Tsin(\alpha)=m\omega^{2}r (2)

a) We can find T usinf the equation (1):

T=\frac {mg}{cos(\alpha)}=\frac{0.04*9.81}{cos(9.44)}=0.40 N

We can find the angular velocity (ω) from the equation (2):

\omega=\sqrt{\frac{Tsin(\alpha)}{mr}}=3.31 rad/s

b) We know that the period is T=2π/ω, therefore:

T=\frac{2\pi}{\omega}=\frac{2\pi}{3.31}=1.9 s

I hope it helps you!

8 0
3 years ago
How would I graph the data in the table on the graph? ********WORTH 50 POINTS********WILL MARK BRAINLIEST**********
Natali5045456 [20]

Answer:

Save the file and try to put stuff over the file. (kinda off like a picture)

3 0
3 years ago
Read 2 more answers
The sun's energy is stored in fossil fuels. true or false.
Scilla [17]
Yes,suns original energy are still stored at the bonds of fossils in which they taken long,long time ago and these fossils powered now industries,fuel for vehicles.In those chemical bonds holds much energy packed together for centuries.
8 0
3 years ago
A model rocket is launched directly upward at a speed of 16 meters per second from a height of 2 meters. The function f(t)=−4.9t
Crank

Answer:

Hmax=15.06 meters

Explanation:The question ask for the maximum value of the function f(t) which can be find by find the maxima of the function

The maxima of the function occurs when the slope is zero. i.e.

\frac{df}{dt} =0\\\frac{df}{dt} =\frac{d}{dt} (-4.9t^2+16t+2)\\\frac{df}{dt} =-4.9*2t+16\\-9.8t+16=0\\t=16/9.8\\t=1.63 secs

Hence the maxima occurs at t=1.63 seconds

The maximum value of f is

f(1.63)=-4.9(1.63^2)+16(1.63)+2\\f(1.63)=15.06\\

hence maximum height is found to be

Hmax=15.06 meters

8 0
3 years ago
How fast is a wave traveling if it has a wavelength of 7 meters and a frequency of 11 Hz?
pashok25 [27]

Answer:

\huge{ \boxed{ \bold{ \sf{77 \: m/s}}}}

☯ Question :

  • How fast is a wave travelling if it has a wavelength of 7 meters and a frequency of 11 Hz?

☯ \underbrace{ \sf{Required \: Answer  :  }}

☥ Given :

  • Wavelength ( λ ) = 7 meters
  • Frequency ( f ) = 11 Hz

☥ To find :

  • Speed of sound ( v ) = ?

☄ We know ,

\boxed{ \sf{v = f \times λ}}

where ,

  • v = speed of sound
  • f = frequency
  • λ = wavelength

Now, substitute the values and solve for v.

➺ \sf{v = 11 \times 7}

➺ \boxed{ \sf{v = 77 \: m/s}}

-------------------------------------------------------------------

✑ Additional Info :

  • Frequency : The number of complete vibrations made by a particle of a body in one second is called it's frequency. It is denoted by the letter f . The SI unit of frequency is hertz ( Hz ).

  • Wavelength : The distance between two consecutive compressions or rarefactions of a sound wave is called wavelength of that wave. It is denoted by λ ( lambda ) and it's SI unit is m.

  • Speed of a sound wave : The distance covered by a sound wave in one second is called speed of sound wave. It depends on the product of wavelength and frequency of the wave.

Hope I helped!

Have a wonderful time! ツ

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7 0
3 years ago
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