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3 years ago

I need help pls help me!!!!

Mathematics

1 answer:

shepuryov [24]3 years ago

7 0

Answer:

208 in squared

Step-by-step explanation:

sorry if it is wrong

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In the isosceles trapezoid below, X = 5x+ 15° 7x-11°

tangare [24]

Answer:

x = 13°

Step-by-step explanation:

5x+15°=7x-11°

5x-7x = -11°-15°

-2x = -26° divide both sides by -2

x = 13°

5x+15° = 5×13°+15° = 80°

7x-11° = 7×13° -11°. = 80°

6 0

2 years ago

If y=14 when x=20, find x when y=3.5

Kruka [31]

I hope this helps you

when y=14 x=20

y=3,5 x=?

?.14=20.3,5

?=20.3,5/14

?=5

7 0

3 years ago

The girl’s hockey team won 6 games, lost 3 games, and tied 2 games. What fraction of the games did they win?

Amanda [17]

They won 6/11 games.

When you add the games they won, lost, and tied you see that they played a total of 11 games. It tells you that they won 6 games so you would put 6 as the numerator and 11 as the denominator and get 6/11.

3 0

3 years ago

Read 2 more answers

What is the value of the function f(x) = 2x – 5 when x = 22? 17 39 49 105

vlabodo [156]

Substitute 22 for x
2(22)-5
44-5
39

4 0

4 years ago

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What other points are on the line of direct variation through (5, 12)? Check all that apply. (0, 0) (2.5, 6) (3, 10) (7.5, 18) (

aalyn [17]

we know that

A relationship between two variables, x, and y, represent a direct variation if it can be expressed in the form $y/x=k$ or $y=kx$

in this problem we have

the point $(5,12)$ is on the line of direct variation

Find the constant of proportionality k

$y/x=k$ -------> substitute ------> $k=12/5$

the equation is

$y=\frac{12}{5}x$

Remember that

If a point is on the line of direct variation

then

the point must satisfy the equation of direct variation

we're proceeding to verify each point

case A) point $(0,0)$

$x=0\ y=0$

Substitute the value of x and y in the direct variation equation

$0=\frac{12}{5}*0$

$0=0$ -------> is true

therefore

the point $(0,0)$ is on the line of direct variation

case B) point $(2.5,6)$

$x=2.5\ y=6$

Substitute the value of x and y in the direct variation equation

$6=\frac{12}{5}*2.5$

$6=6$ -------> is true

therefore

the point $(2.5,6)$ is on the line of direct variation

case C) point $(3,10)$

$x=3\ y=10$

Substitute the value of x and y in the direct variation equation

$10=\frac{12}{5}*3$

$10=7.2$ -------> is not true

therefore

the point $(3,10)$ is not on the line of direct variation

case D) point $(7.5,18)$

$x=7.5\ y=18$

Substitute the value of x and y in the direct variation equation

$18=\frac{12}{5}*7.5$

$18=18$ -------> is true

therefore

the point $(7.5,18)$ is on the line of direct variation

case E) point $(12.5,24)$

$x=12.5\ y=24$

Substitute the value of x and y in the direct variation equation

$24=\frac{12}{5}*12.5$

$18=30$ -------> is not true

therefore

the point $(12.5,24)$ is not on the line of direct variation

case F) point $(15,36)$

$x=15\ y=36$

Substitute the value of x and y in the direct variation equation

$36=\frac{12}{5}*15$

$36=36$ -------> is true

therefore

the point $(15,36)$ is on the line of direct variation

therefore

the answer is

$(0,0)$

$(2.5,6)$

$(7.5,18)$

$(15,36)$

5 0

3 years ago

Read 2 more answers