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polet [3.4K]
3 years ago
13

I need help people get brailestttt

Mathematics
1 answer:
vova2212 [387]3 years ago
7 0

Answer:

Whats the question?

Step-by-step explanation:

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3.<br> B<br> С<br> A<br> D<br> E<br> How many rays intersect at point o?
swat32
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4 years ago
Read 2 more answers
Round to the nearest half 6.385
iragen [17]

Answer:

6.5

Step-by-step explanation:

I hope you have a great day!!

3 0
3 years ago
The area under a particular normal curve between 6 and 8 is 0.695. A normally distributed variable has the same mean and standar
TiliK225 [7]

Answer:

69.5%

Step-by-step explanation:

A feature of the normal distribution is that this is completely determined by its mean and standard deviation, therefore, if two normal curves have the same mean and standard deviation we can be sure that they are the same normal curve. Then, the probability of getting a value of the normally distributed variable between 6 and 8 is 0.695. In practice we can say that if we get a large sample of observations of the variable, then, the percentage of all possible observations of the variable that lie between 6 and 8 is 100(0.695)% = 69.5%.

4 0
3 years ago
Someone help :(( thank youuuu so much if u do
VMariaS [17]

Answer:

-10

Step-by-step explanation:

The equation would be -8 - (-10) = 2. When subtracting a negative, you are actually just adding a positive. It's like the two negative signs cancel each other out, so it would look more like -8 + 10 = 2. For the answer box, just put -10.

5 0
3 years ago
What is the length of the conjugate axis?<br> <img src="https://tex.z-dn.net/?f=%5Cfrac%7B%28x-2%29%5E2%7D%7B36%7D%20-%20%5Cfrac
LuckyWell [14K]

Answer:

the length of the conjugate axis  is 16

Step-by-step explanation:

We know that the general equation of a hyperbola with transverse horizontal axis has the form:

\frac{(x-h)^2}{a^2} - \frac{(y-k)^2}{b^2} = 1

Where the point (h, k) are the coordinates of the center of the ellipse

2a is the length of the transverse horizontal axis

2b is the length of the conjugate axis

In this case the equation of the ellipse is:

\frac{(x-2)^2}{36} + \frac{(y+1)^2}{64} = 1

Then

b^2 = 64\\\\b = \sqrt{64}\\\\b = 8\\\\2b = 16

Finally the length of the conjugate axis is 16

5 0
3 years ago
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