All categories

3 years ago

I need help people get brailestttt

Mathematics

1 answer:

vova2212 [387]3 years ago

7 0

Answer:

Whats the question?

Step-by-step explanation:

You might be interested in

Priya has completed 9 exam questions this is 60% of the questions on the exam. Write an equation representing this situation. Ex

krek1111 [17]

Answer:

9=0.6q where q is the number of questions on the exam.

Step-by-step explanation:

3 0

3 years ago

In the morning, the temperature was 15∘F. During the day, the temperature fell 37 degrees. Which expression shows how to find th

tino4ka555 [31]

Answer:

- 22°F

Step-by-step explanation:

Given that :

Morning temperature = 15°F

Change in temperature = fall by 37 degree

The temperature of the end of the day:

Morning temperature + (change in temperature)

Fall by 37° = decrease in temperature by 37° = - 37°

15°F + (-37°F)

15°F - 37°F

= - 22°F

6 0

3 years ago

Can any one help me on this? Please thank you

nignag [31]

The area of a triangle is base length x height then divide all by 2,
so 12 x 10 /2
=60 ft²

5 0

3 years ago

Choose the correct simplification of the expression (b^5)4

tangare [24]

Answer:

b^20

Step-by-step explanation:

when the exponents have one inside and the other outside, they are multiplied.

8 0

3 years ago

Use the model below to estimate the average annual growth rate of a certain country's population for 1950, 1988, and 2010, where

Morgarella [4.7K]

Answer:

The average annual growth rate of a certain country's population for 1950, 1988, and 2010 are 2.398, 0.9985 and 0.2236 respectively.

Step-by-step explanation:

The given equation is

$Y=-0.0000084x^3+0.00211x^2-0.205x+8.423$

Where Y is the annual growth rate of a certain country's population and x is the number of years after 1900.

Difference between 1950 and 1900 is 50.

Put x=50 in the given equation.

$Y=-0.0000084(50)^3+0.00211(50)^2-0.205(50)+8.423$

$Y=2.398$

Therefore the estimated average annual growth rate of the country's population for 1950 is 2.398.

Difference between 1988 and 1900 is 88.

Put x=88 in the given equation.

$Y=-0.0000084(88)^3+0.00211(88)^2-0.205(88)+8.423$

$Y=0.9984752\approx 0.9985$

Therefore the estimated average annual growth rate of the country's population for 1988 is 0.9985.

Difference between 2010 and 1900 is 110.

Put x=110 in the given equation.

$Y=-0.0000084(110)^3+0.00211(110)^2-0.205(110)+8.423$

$Y=0.2236$

Therefore the estimated average annual growth rate of the country's population for 2010 is 0.2236.

8 0

3 years ago