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Arte-miy333 [17]
3 years ago
15

Can someone help me find the perimeter and area of the shape or figure?

Mathematics
1 answer:
MA_775_DIABLO [31]3 years ago
6 0

0.7 + 0.4 + 0.6 + 0.4 = 2.1 is the perimeter

0.7 x 0.4 = 0.28

0.6 x 0.4 = 0.24

0.28 + 0.24 = 0.52 is the area

Hope that helped!

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25 feet

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8⅓ yards

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Calculate the force when the pressure is 18 N/M squared and the area is 4 M squared.
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The force is 72 Newton
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Help please asap!! will mark correct answer first brainliest! 25 POINTS.. FIRST SOLVE THE QUESTION WITH THE PICTURE THAN THE ONE
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1. Eyeballing the data, the best fit will be pretty close to a line between the leftmost point and the rightmost point.

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y = (250/24) x+ (4280/24)

Approximately that's,

y = 10.4 x + 178

Answer: 4th choice, 10.4x + 180

2. For 48 wheelbarrows,

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Answer: 679.2 liters of sand

4 0
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A store owner puts in an order for product X and product Y for a total of 4,000 units. It costs $0.10 per item to ship of produc
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A maritime flag is shown. What is the area of the shaded part of the flag? Explain
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Answer:

<em></em>Area = 72in^2<em></em>

<em></em>

Step-by-step explanation:

<em>Your question is incomplete without an attachment (See attachment)</em>

Required

Determine the area of the shaded part

From the attachment;

<em>Assume that the shaded portion is closed to the right;</em>

<em>Calculate  the Area:</em>

<em></em>Area_1 = Length * Width<em></em>

<em></em>Area_2 = 8in * (6in + 6in)<em></em>

<em></em>Area_2 = 8in * 12in<em></em>

<em></em>Area_1 = 96in^2<em></em>

<em></em>

<em>Next;</em>

<em>Calculate the Area of the imaginary triangle (on the right)</em>

<em></em>Area_2 = \frac{1}{2} * base * height<em></em>

<em></em>Area_2 = \frac{1}{2} * (6in + 6in) * 4in<em></em>

<em></em>Area_2 = \frac{1}{2} * 12in * 4in<em></em>

<em></em>Area_2 = \frac{1}{2} * 48in^2<em></em>

<em></em>Area_2 = 24in^2<em></em>

<em></em>

<em>Lastly, calculate the Area of the Shaded Part</em>

<em></em>Area = Area_1 - Area_2<em></em>

<em></em>Area = 96in^2 - 24in^2<em></em>

<em></em>Area = 72in^2<em></em>

<em></em>

<em>Hence,</em>

<em>The area of the shaded part is 72in²</em>

3 0
3 years ago
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