L=2W+3, A=LW, using L from the first in the second gives you:
A=(2W+3)W
A=2W^2+3W, and we are told A=90 so
2W^2+3W=90
2W^2+3W-90=0
2W^2-12W+15W-90=0
2W(W-6)+15(W-6)=0
(2W+15)(W-6)=0, since W>0 for all real possibilities,
W=6ft, and since L=2W+3
L=15ft
So the pool will be 6 ft wide by 15 ft long.
V=(1/3)πr²h
∴ dV/dt
=(π/3)[r²(dh/dt)+h2r(dr/dt)]
=(π/3)[(30)²(-2)+40(2)(30)(2)]
=(π/3)[-1800+4800]
=1600π in³/sec
Answer: 1600π in³/sec
Sandra ran 7/12 of a mile. Lamar ran 3/4 of a mile. Who ran further?
Lamar ran further.
3/4=(3*3)/(4*3) which equals 9/12.
Based off calculations we also see that 9/12>7/12.
Which then leaves us too 3/4>7/12.
Answer:
q = 9
Step-by-step explanation:
5 + 3(q - 4) = 2(q + 1)
To solve, you need to get q by itself on one side.
5 + 3q - 12 = 2q + 2 --- distribute the multipliers next to the parenthesis
3q - 7 = 2q + 2 --- combine like terms
q - 7 = 2 --- subtract 2q from both sides
q = 9 --- add 7 to both sides
I think it is (5, -4)... not completely sure though
