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2 years ago

What is the length of the diagonal of the rectangular solid shown? please help!!!!

Mathematics

1 answer:

Olin [163]2 years ago

7 0

Answer:

D. diagonal = 20.10 cm

Step-by-step explanation:

Find the bottom diagonal using the length and width.

diagonal² = 8² + 12²

diagonal = √64+144

diagonal = √208

diagonal = 4√13

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Find diagonal of the rectangular solid:

diagonal² = (4√13)² + 14²

diagonal² = 208 + 196

diagonal = √404

diagonal = 20.10 cm

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3 years ago

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Through: (-3,0), perp. to y = 3x - 1

Marrrta [24]

Answer:

$y=-\dfrac{1}{3}x-1$

Step-by-step explanation:

Given:

line y=3x-1

point (-3,0)

Write: equation of the line that is perpendicular to the given and passes through the point (-3,0)

Solution:

The slope of the given line is $m=3$

If $m_1$ is the slope of perpendicular line, then

$m\cdot m_1=-1\\ \\3m_1=-1\\ \\m_1=-\dfrac{1}{3}$

So, the equation of the needed line is $y=-\dfrac{1}{3}x+b.$

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$0=-\dfrac{1}{3}\cdot (-3)+b\\ \\0=1+b\\ \\b=-1\\ \\y=-\dfrac{1}{3}x-1$

7 0

3 years ago

Eva wants to make two pieces of pottery.She needs 3/5 pound of clay for one piece and 7/10 pound of clay for the other piece.She

marta [7]

Answer:

a) Eva will need 2 bags of clay to make both pieces of pottery.

b) She will have leftover $\frac{11}{10}$ pounds of clay.

Step-by-step explanation:

a) We have to find the total amount of clay, as she needs $\frac{3}{5}pound=P_{1}$ and $\frac{7}{10}pound=P_{2}$ , so $P_{1}+P_{2}= \frac{3}{5} +\frac{7}{10} =\frac{6+7}{10}=\frac{13}{10}pounds$ , is the total amount of clay. Then as we Know that one bag of clay has $\frac{4}{5} =\frac{8}{10} pounds$ , It isn´t enough, but with two bags $2*\frac{8}{10}=\frac{16}{10} pounds$ , It is enough clay.

b) She will have leftover $\frac{16}{10} -\frac{13}{10} =\frac{3}{10}pounds$ of the second bag, then we add the third one, so $\frac{3}{10} +\frac{8}{10} =\frac{11}{10}pounds$ are leftover.