A chemist has one solution that is 20% alcohol and another that is 60% alcohol.
1 answer:
Answer:
solution 1= 40ml
solution 2= 160ml
Step-by-step explanation:
%alcohol= amount of alcohol/total solutionx100
0.52x200=104ml of alcohol present
0.2x L=0.2Lml of alcohol in solution one
0.6 x M=0.6Mml of alcohol in solution two
1st equation
0.2L+0.6M=104ml alcohol
times 10 to get whole
2L+6M=1040ml
2nd
same for this equation
10L+10M=2000ml
10L+10M=2000
2L+6M=1040
elimination method
=20L+20M=4000
-
=20L+60M=10400
-40M=-6400
M=160ml
2L+6 (160)=1040
2L=1040-960
2L=80
L=40ml
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